Files
JavaScript/Dynamic-Programming/LongestPalindromicSubsequence.js
Roland Hummel 86d333ee94 feat: Test running overhaul, switch to Prettier & reformat everything (#1407)
* chore: Switch to Node 20 + Vitest

* chore: migrate to vitest mock functions

* chore: code style (switch to prettier)

* test: re-enable long-running test

Seems the switch to Node 20 and Vitest has vastly improved the code's and / or the test's runtime!

see #1193

* chore: code style

* chore: fix failing tests

* Updated Documentation in README.md

* Update contribution guidelines to state usage of Prettier

* fix: set prettier printWidth back to 80

* chore: apply updated code style automatically

* fix: set prettier line endings to lf again

* chore: apply updated code style automatically

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Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
2023-10-04 02:38:19 +05:30

34 lines
779 B
JavaScript

/*
LeetCode -> https://leetcode.com/problems/longest-palindromic-subsequence/
Given a string s, find the longest palindromic subsequence's length in s.
You may assume that the maximum length of s is 1000.
*/
export const longestPalindromeSubsequence = function (s) {
const n = s.length
const dp = new Array(n)
.fill(0)
.map((item) => new Array(n).fill(0).map((item) => 0))
// fill predefined for single character
for (let i = 0; i < n; i++) {
dp[i][i] = 1
}
for (let i = 1; i < n; i++) {
for (let j = 0; j < n - i; j++) {
const col = j + i
if (s[j] === s[col]) {
dp[j][col] = 2 + dp[j + 1][col - 1]
} else {
dp[j][col] = Math.max(dp[j][col - 1], dp[j + 1][col])
}
}
}
return dp[0][n - 1]
}