Files
JavaScript/String/IsPalindrome.js
Roland Hummel 86d333ee94 feat: Test running overhaul, switch to Prettier & reformat everything (#1407)
* chore: Switch to Node 20 + Vitest

* chore: migrate to vitest mock functions

* chore: code style (switch to prettier)

* test: re-enable long-running test

Seems the switch to Node 20 and Vitest has vastly improved the code's and / or the test's runtime!

see #1193

* chore: code style

* chore: fix failing tests

* Updated Documentation in README.md

* Update contribution guidelines to state usage of Prettier

* fix: set prettier printWidth back to 80

* chore: apply updated code style automatically

* fix: set prettier line endings to lf again

* chore: apply updated code style automatically

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Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
2023-10-04 02:38:19 +05:30

38 lines
1.4 KiB
JavaScript

/**
* @function isPalindromeIterative
* @description isPalindromeIterative function checks whether the provided input is palindrome or not
* @param {String | Number} x - The input to check
* @return {boolean} - Input is palindrome or not
* @see [Palindrome](https://en.wikipedia.org/wiki/Palindrome)
*/
/*
* Big-O Analysis
* Time Complexity
- O(N) on average and worst case scenario as input is traversed in linear fashion
- O(1) on best case scenario if the input already is a string (otherwise toString() method takes O(N))
and the first & last characters don't match, triggering an early return
* Space Complexity
- O(1)
*/
export function isPalindromeIterative(x) {
if (typeof x !== 'string' && typeof x !== 'number') {
throw new TypeError('Input must be a string or a number')
}
// Convert x to string whether it's number or string
const string = x.toString()
const length = string.length
if (length === 1) return true
// Apply two pointers technique to compare first and last elements on each iteration
for (let start = 0, end = length - 1; start < end; start++, end--) {
// Early return if compared items are different, input is not a palindrome
if (string[start] !== string[end]) return false
}
// If early return in condition inside for loop is not reached, then input is palindrome
return true
}