/** * Problem 44 - Pentagon numbers * * @see {@link https://projecteuler.net/problem=44} * * Pentagonal numbers are generated by the formula, Pn=n(3nāˆ’1)/2. The first ten pentagonal numbers are: * 1, 5, 12, 22, 35, 51, 70, 92, 117, 145, ... * It can be seen that P4 + P7 = 22 + 70 = 92 = P8. However, their difference, 70 āˆ’ 22 = 48, is not pentagonal. * Find the pair of pentagonal numbers, Pj and Pk, for which their sum and difference are pentagonal and D = |Pk āˆ’ Pj| is minimised; what is the value of D? * * @author ddaniel27 */ function problem44(k) { if (k < 1) { throw new Error('Invalid Input') } while (true) { k++ const n = (k * (3 * k - 1)) / 2 // calculate Pk for (let j = k - 1; j > 0; j--) { const m = (j * (3 * j - 1)) / 2 // calculate all Pj < Pk if (isPentagonal(n - m) && isPentagonal(n + m)) { // Check sum and difference return n - m // return D } } } } /** * Function to check if a number is pentagonal or not * This function solves n * applying the solution for a quadratic function * @see {@link https://en.wikipedia.org/wiki/Quadratic_function} */ function isPentagonal(n) { const pent = (Math.sqrt(24 * n + 1) + 1) / 6 return pent === Math.floor(pent) } export { problem44 }