Merge pull request #769 from SyedFasiuddin/master

Adding an algorithm AlphaNumericPalindrome from freecodecamp
This commit is contained in:
Christian Clauss
2021-10-20 15:33:27 +02:00
committed by GitHub
2 changed files with 77 additions and 0 deletions

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/**
* alphaNumericPlaindrome should return true if the string has alphanumeric characters that are palindrome irrespective of special characters and the letter case
* @param {string} str the string to check
* @returns `Boolean`
*/
/*****************************************************************************
* What is a palindrome? https://en.wikipedia.org/wiki/Palindrome
*
* The function alphaNumericPlaindrome() recieves a sting with varying formats
* like "racecar", "RaceCar", and "race CAR"
* The string can also have special characters
* like "2A3*3a2", "2A3 3a2", and "2_A3*3#A2"
*
* But the catch is, we have to check only if the alphanumeric characters
* are palindrome i.e remove spaces, symbols, punctuations etc
* and the case of the characters doesn't matter
*
* This is one of the questions/projects that we have to solve for the
* JavaScript Algorithms and Data Structures course on https://www.freecodecamp.org
*
* Author -- Syed Fasiuddin
* https://github.com/SyedFasiuddin
*
****************************************************************************/
const alphaNumericPlaindrome = (str) => {
// removing all the special characters and turning everything to lowercase
const newStr = str.replace(/[^a-zA-Z0-9]*/g, '').toLowerCase()
// the newStr variable is a string and only has alphanumeric characters all in lowercase
// making an array of individual characters as it's elements
const arr = newStr.split('')
// setting a variable to see if change occurs to it
let palin = 0
// making a copy of arr with spread operator
const arrRev = [...arr]
// you can use arrRev.reverse() to reverse the array
// or else you can use the below method
// iterate through the arr and check the condition of palindrome
for (let i = 0; i < arr.length; i++) {
if (arr[i] !== arrRev[arr.length - 1 - i]) {
// if the string is not palindrome then we change palin varaible to 1
palin = 1
}
}
// if the string is palindrome then palin variable is never changed
if (palin === 0) return true
else return false
}
export { alphaNumericPlaindrome }

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import { alphaNumericPlaindrome } from '../AlphaNumericPalindrome'
test('should return true if the given string has alphanumeric characters that are palindrom irrespective of case and symbols', () => {
expect(alphaNumericPlaindrome('eye')).toBe(true)
})
test('should return true if the given string has alphanumeric characters that are palindrom irrespective of case and symbols', () => {
expect(alphaNumericPlaindrome('0_0 (: /-:) 0-0')).toBe(true)
})
test('should return true if the given string has alphanumeric characters that are palindrom irrespective of case and symbols', () => {
expect(alphaNumericPlaindrome('five|_/|four')).toBe(false)
})
test('should return true if the given string has alphanumeric characters that are palindrom irrespective of case and symbols', () => {
expect(alphaNumericPlaindrome('A man, a plan, a canal. Panama')).toBe(true)
})
test('should return true if the given string has alphanumeric characters that are palindrom irrespective of case and symbols', () => {
expect(alphaNumericPlaindrome('1 eye for of 1 eye.')).toBe(false)
})