0 1 knapsack (#408)

* Added Longest Common Subsequence

* Renamed the File

* Optimized the code

* Optimized the code

* Changed some styles as per the rule

* Again some style fixed

* Added Longest Increasing Subsequence program to the list

* Style changed

* Added 0-1-Knapsack Problem

* Style Changed as per guidelines

* Update ZeroOneKnapsack.js

* Delete LongestCommonSubsequence.js

* Delete LongestIncreasingSubsequence.js

Co-authored-by: vinayak <itssvinayak@gmail.com>
This commit is contained in:
Omkarnath Parida
2020-10-04 23:03:48 +05:30
committed by GitHub
parent fa01faf207
commit c9169dc16f

View File

@ -0,0 +1,71 @@
/**
* A Dynamic Programming based solution for calculating Zero One Knapsack
* https://en.wikipedia.org/wiki/Knapsack_problem
*/
const zeroOneKnapsack = (arr, n, cap, cache) => {
if (cap === 0 || n === 0) {
cache[n][cap] = 0
return cache[n][cap]
}
if (cache[n][cap] !== -1) {
return cache[n][cap]
}
if (arr[n - 1][0] <= cap) {
cache[n][cap] = Math.max(arr[n - 1][1] + zeroOneKnapsack(arr, n - 1, cap - arr[n - 1][0], cache), zeroOneKnapsack(arr, n - 1, cap, cache))
return cache[n][cap]
} else {
cache[n][cap] = zeroOneKnapsack(arr, n - 1, cap, cache)
return cache[n][cap]
}
}
const main = () => {
/*
Problem Statement:
You are a thief carrying a single bag with limited capacity S. The museum you stole had N artifact that you could steal. Unfortunately you might not be able to steal all the artifact because of your limited bag capacity.
You have to cherry pick the artifact in order to maximize the total value of the artifacts you stole.
Link for the Problem: https://www.hackerrank.com/contests/srin-aadc03/challenges/classic-01-knapsack
*/
let input = `1
4 5
1 8
2 4
3 0
2 5
2 3`
input = input.trim().split('\n')
input.shift()
const length = input.length
let i = 0
while (i < length) {
const cap = Number(input[i].trim().split(' ')[0])
const currlen = Number(input[i].trim().split(' ')[1])
let j = i + 1
const arr = []
while (j <= i + currlen) {
arr.push(input[j])
j++
}
const newArr = []
arr.map(e => {
newArr.push(e.trim().split(' ').map(Number))
})
const cache = []
for (let i = 0; i <= currlen; i++) {
const temp = []
for (let j = 0; j <= cap; j++) {
temp.push(-1)
}
cache.push(temp)
}
const result = zeroOneKnapsack(newArr, currlen, cap, cache)
console.log(result)
i += currlen + 1
}
}
main()