merge: Binary Convert (#865)

* Binary Convert

* Update link

* add more test cases

Maths/BinaryConvert.js

@@ -1,10 +1,25 @@
-const BinaryConvert = (number) => {
+/**
-  const result = []
+ * @function BinaryConvert
-  let i
+ * @description Convert the decimal to binary.
-  for (i = number; i > 0; i = parseInt(i / 2)) {
+ * @param {Integer} num - The input integer
-    result.push(i % 2) // push the value (remainder)to array
+ * @return {Integer} - Binary of num.
-  } return Number(result.reverse().join(''))
+ * @see [BinaryConvert](https://www.programiz.com/javascript/examples/decimal-binary)
-  // reverse index of array as string ,join and change the type of value to become Number
+ * @example BinaryConvert(12) = 1100
+ * @example BinaryConvert(12 + 2) = 1110
+ */
+
+const BinaryConvert = (num) => {
+  let power = 1
+  let binary = 0
+
+  while (num) {
+    const rem = num % 2
+    num = Math.floor(num / 2)
+    binary = rem * power + binary
+    power *= 10
+  }
+
+  return binary
 }
-// call function and value as parameter to passing the value
+
 export { BinaryConvert }

Maths/test/BInaryConvert.test.js

@@ -1,10 +1,22 @@
 import { BinaryConvert } from '../BinaryConvert'
 
-describe('Binary Convert', () => {
+describe('BinaryConvert', () => {
+  it('should return the correct value', () => {
+    expect(BinaryConvert(4)).toBe(100)
+  })
   it('should return the correct value', () => {
     expect(BinaryConvert(12)).toBe(1100)
   })
   it('should return the correct value of the sum from two number', () => {
     expect(BinaryConvert(12 + 2)).toBe(1110)
   })
+  it('should return the correct value of the subtract from two number', () => {
+    expect(BinaryConvert(245 - 56)).toBe(10111101)
+  })
+  it('should return the correct value', () => {
+    expect(BinaryConvert(254)).toBe(11111110)
+  })
+  it('should return the correct value', () => {
+    expect(BinaryConvert(63483)).toBe(1111011111111011)
+  })
 })