merge: Implement Add Two Numbers (Linked List) (#888)

* Implement Add Two Numbers (Linked List)

* Implement Add Two Numbers (Linked List)

* Implement Add Two Numbers (Linked List)

Co-authored-by: Shakil Ahmmed <shakilahmmed@ShakilAhmmeds-MacBook-Pro.local>
This commit is contained in:
Shakil Ahmmed
2022-02-17 17:59:36 +06:00
committed by GitHub
parent c9701e8a4c
commit 9911410e70
3 changed files with 86 additions and 1 deletions

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/**
* A LinkedList based solution for Add Two Numbers
*
*/
import { Node } from './SinglyLinkedList.js'
/*
Problem Statement:
Given two non-empty linked lists representing two non-negative integers.
The digits are stored in reverse order and each of their nodes contain a single digit.
Add the two numbers and return it as a linked list.
Link for the Problem: https://leetcode.com/problems/add-two-numbers/
*/
class AddTwoNumbers {
constructor () {
this.dummyNode = new Node(0)
}
solution (firstList, secondList) {
let firstRunner = firstList
let secondRunner = secondList
let tail = this.dummyNode
let carry = 0
while (firstRunner != null || secondRunner != null) {
const firstNumber = firstRunner ? firstRunner.data : 0
const secondNumber = secondRunner ? secondRunner.data : 0
const sum = carry + firstNumber + secondNumber
carry = parseInt(sum / 10)
tail.next = new Node(sum % 10)
tail = tail.next
if (firstRunner) {
firstRunner = firstRunner.next
}
if (secondRunner) {
secondRunner = secondRunner.next
}
}
if (carry > 0) {
tail.next = new Node(carry % 10)
}
return this.dummyNode.next
}
solutionToArray () {
const list = []
let currentNode = this.dummyNode.next
while (currentNode) {
list.push(currentNode.data)
currentNode = currentNode.next
}
return list
}
}
export { AddTwoNumbers }