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feat: Test running overhaul, switch to Prettier & reformat everything (#1407)

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* chore: Switch to Node 20 + Vitest

* chore: migrate to vitest mock functions

* chore: code style (switch to prettier)

* test: re-enable long-running test

Seems the switch to Node 20 and Vitest has vastly improved the code's and / or the test's runtime!

see #1193

* chore: code style

* chore: fix failing tests

* Updated Documentation in README.md

* Update contribution guidelines to state usage of Prettier

* fix: set prettier printWidth back to 80

* chore: apply updated code style automatically

* fix: set prettier line endings to lf again

* chore: apply updated code style automatically

---------

Co-authored-by: github-actions <${GITHUB_ACTOR}@users.noreply.github.com>
Co-authored-by: Lars Müller <34514239+appgurueu@users.noreply.github.com>
This commit is contained in:
Roland Hummel
2023-10-03 23:08:19 +02:00
committed by GitHub
parent 0ca18c2b2c
commit 86d333ee94
392 changed files with 5849 additions and 16622 deletions
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38
Project-Euler/Problem028.js
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@ -17,7 +17,7 @@
* @author ddaniel27
*/
function problem28 (dim) {
function problem28(dim) {
if (dim % 2 === 0) {
throw new Error('Dimension must be odd')
}
@ -28,24 +28,24 @@ function problem28 (dim) {
let result = 1
for (let i = 3; i <= dim; i += 2) {
/**
* Adding more dimensions to the matrix, we will find at the top-right corner the follow sequence:
* 01, 09, 25, 49, 81, 121, 169, ...
* So this can be expressed as:
* i^2, where i is all odd numbers
*
* Also, we can know which numbers are in each corner dimension
* Just develop the sequence counter clockwise from top-right corner like this:
* First corner: i^2
* Second corner: i^2 - (i - 1) | The "i - 1" is the distance between corners in each dimension
* Third corner: i^2 - 2 * (i - 1)
* Fourth corner: i^2 - 3 * (i - 1)
*
* Doing the sum of each corner and simplifying, we found that the result for each dimension is:
* sumDim = 4 * i^2 + 6 * (1 - i)
*
* In this case I skip the 1x1 dim matrix because is trivial, that's why I start in a 3x3 matrix
*/
result += (4 * i * i) + 6 * (1 - i) // Calculate sum of each dimension corner
* Adding more dimensions to the matrix, we will find at the top-right corner the follow sequence:
* 01, 09, 25, 49, 81, 121, 169, ...
* So this can be expressed as:
* i^2, where i is all odd numbers
*
* Also, we can know which numbers are in each corner dimension
* Just develop the sequence counter clockwise from top-right corner like this:
* First corner: i^2
* Second corner: i^2 - (i - 1) | The "i - 1" is the distance between corners in each dimension
* Third corner: i^2 - 2 * (i - 1)
* Fourth corner: i^2 - 3 * (i - 1)
*
* Doing the sum of each corner and simplifying, we found that the result for each dimension is:
* sumDim = 4 * i^2 + 6 * (1 - i)
*
* In this case I skip the 1x1 dim matrix because is trivial, that's why I start in a 3x3 matrix
*/
result += 4 * i * i + 6 * (1 - i) // Calculate sum of each dimension corner
}
return result
}