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refactor: use isLeapYear (#1638)

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This commit is contained in:
Piotr Idzik
2024-03-07 05:53:43 +01:00
committed by GitHub
parent d8cfdcd800
commit 4a4ed57d42
3 changed files with 34 additions and 23 deletions
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9
Timing-Functions/GetMonthDays.js
View File

@ -6,6 +6,8 @@
e.g.: mahfoudh.arous.com ->false
*/
import { isLeapYear } from '../Maths/LeapYear'
const getMonthDays = (monthNumber, year) => {
const the31DaysMonths = [1, 3, 5, 7, 8, 10, 12]
const the30DaysMonths = [4, 6, 9, 11]
@ -26,11 +28,8 @@ const getMonthDays = (monthNumber, year) => {
return 30
}
// Check for Leap year
if (year % 4 === 0) {
if (year % 100 !== 0 || (year % 100 === 0 && year % 400 === 0)) {
return 29
}
if (isLeapYear(year)) {
return 29
}
return 28

37
Timing-Functions/test/GetMonthDays.test.js
View File

@ -1,16 +1,33 @@
import { getMonthDays } from '../GetMonthDays'
describe('Get the Days of a Month', () => {
it('expects to return 28', () => {
expect(getMonthDays(2, 2018)).toEqual(28)
})
it('expects to return 30', () => {
expect(getMonthDays(6, 254)).toEqual(30)
})
it('expects to return 29', () => {
expect(getMonthDays(2, 2024)).toEqual(29)
it.each([
[1, 2024, 31],
[2, 2024, 29],
[3, 2024, 31],
[4, 2024, 30],
[5, 2024, 31],
[6, 2024, 30],
[7, 2024, 31],
[8, 2024, 31],
[9, 2024, 30],
[10, 2024, 31],
[11, 2024, 30],
[12, 2024, 31],
[1, 2023, 31],
[2, 2023, 28],
[3, 2023, 31],
[4, 2023, 30],
[5, 2023, 31],
[6, 2023, 30],
[7, 2023, 31],
[8, 2023, 31],
[9, 2023, 30],
[10, 2023, 31],
[11, 2023, 30],
[12, 2023, 31]
])('Month %i in year %i has %i days', (month, year, expected) => {
expect(getMonthDays(month, year)).toBe(expected)
})
it('expects to throw a type error', () => {