mirror of
https://github.com/TheAlgorithms/JavaScript.git
synced 2025-07-05 00:01:37 +08:00
Added Longest Plaindromic subsequence
This commit is contained in:
39
Dynamic-Programming/LongestPalindromicSubsequence.js
Normal file
39
Dynamic-Programming/LongestPalindromicSubsequence.js
Normal file
@ -0,0 +1,39 @@
|
|||||||
|
/*
|
||||||
|
LeetCode -> https://leetcode.com/problems/longest-palindromic-subsequence/
|
||||||
|
|
||||||
|
Given a string s, find the longest palindromic subsequence's length in s.
|
||||||
|
You may assume that the maximum length of s is 1000.
|
||||||
|
|
||||||
|
*/
|
||||||
|
|
||||||
|
const longestPalindromeSubsequence = function (s) {
|
||||||
|
const n = s.length
|
||||||
|
|
||||||
|
const dp = new Array(n).fill(0).map(item => new Array(n).fill(0).map(item => 0))
|
||||||
|
|
||||||
|
// fill predefined for single character
|
||||||
|
for (let i = 0; i < n; i++) {
|
||||||
|
dp[i][i] = 1
|
||||||
|
}
|
||||||
|
|
||||||
|
for (let i = 1; i < n; i++) {
|
||||||
|
for (let j = 0; j < n - i; j++) {
|
||||||
|
const col = j + i
|
||||||
|
if (s[j] == s[col]) {
|
||||||
|
dp[j][col] = 2 + dp[j + 1][col - 1]
|
||||||
|
} else {
|
||||||
|
dp[j][col] = Math.max(dp[j][col - 1], dp[j + 1][col])
|
||||||
|
}
|
||||||
|
}
|
||||||
|
}
|
||||||
|
|
||||||
|
return dp[0][n - 1]
|
||||||
|
}
|
||||||
|
|
||||||
|
const main = () => {
|
||||||
|
console.log(longestPalindromeSubsequence('bbbab')) // 4
|
||||||
|
console.log(longestPalindromeSubsequence('axbya')) // 3
|
||||||
|
console.log(longestPalindromeSubsequence('racexyzcxar')) // 7
|
||||||
|
}
|
||||||
|
|
||||||
|
main()
|
Reference in New Issue
Block a user