Added Maximum product of 3 numbers in an array

Dynamic-Programming/MaxProductOfThree.js

@@ -0,0 +1,37 @@
+/**
+ *  Given an array of numbers, return the maximum product
+ *  of 3 numbers from the array
+ * @param {number[]} arrayItems
+ * @returns number
+ */
+export function maxProductOfThree(arrayItems) {
+  // if size is less than 3, no triplet exists
+  let n = arrayItems.length
+  if (n < 3) return -1
+  let max1 = arrayItems[0],
+    max2 = -1,
+    max3 = -1,
+    min1 = arrayItems[0],
+    min2 = -1
+  for (let i = 1; i < n; i++) {
+    if (arrayItems[i] > max1) {
+      max3 = max2
+      max2 = max1
+      max1 = arrayItems[i]
+    } else if (max2 === -1 || arrayItems[i] > max2) {
+      max3 = max2
+      max2 = arrayItems[i]
+    } else if (max3 === -1 || arrayItems[i] > max3) {
+      max3 = arrayItems[i]
+    }
+    if (arrayItems[i] < min1) {
+      min2 = min1
+      min1 = arrayItems[i]
+    } else if (min2 === -1 || arrayItems[i] < min2) {
+      min2 = arrayItems[i]
+    }
+  }
+  let prod1 = max1 * max2 * max3,
+    prod2 = max1 * min1 * min2
+  return Math.max(prod1, prod2)
+}