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Added Maximum product of 3 numbers in an array
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37
Dynamic-Programming/MaxProductOfThree.js
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37
Dynamic-Programming/MaxProductOfThree.js
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/**
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* Given an array of numbers, return the maximum product
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* of 3 numbers from the array
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* @param {number[]} arrayItems
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* @returns number
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*/
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export function maxProductOfThree(arrayItems) {
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// if size is less than 3, no triplet exists
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let n = arrayItems.length
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if (n < 3) return -1
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let max1 = arrayItems[0],
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max2 = -1,
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max3 = -1,
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min1 = arrayItems[0],
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min2 = -1
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for (let i = 1; i < n; i++) {
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if (arrayItems[i] > max1) {
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max3 = max2
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max2 = max1
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max1 = arrayItems[i]
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} else if (max2 === -1 || arrayItems[i] > max2) {
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max3 = max2
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max2 = arrayItems[i]
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} else if (max3 === -1 || arrayItems[i] > max3) {
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max3 = arrayItems[i]
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}
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if (arrayItems[i] < min1) {
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min2 = min1
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min1 = arrayItems[i]
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} else if (min2 === -1 || arrayItems[i] < min2) {
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min2 = arrayItems[i]
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}
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}
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let prod1 = max1 * max2 * max3,
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prod2 = max1 * min1 * min2
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return Math.max(prod1, prod2)
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}
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15
Dynamic-Programming/tests/MaxProductOfThree.test.js
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15
Dynamic-Programming/tests/MaxProductOfThree.test.js
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import { maxProductOfThree } from '../MaxProductOfThree'
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describe('MaxProductOfThree', () => {
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it('expects to return -1 for array with only 2 numbers', () => {
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expect(maxProductOfThree([1, 3])).toBe(-1)
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})
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it('expects to return 300 as the maximum product', () => {
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expect(maxProductOfThree([10, 6, 5, 3, 1, -10])).toBe(300)
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})
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it('expects to return 300 as the maximum product', () => {
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expect(maxProductOfThree([10, -6, 5, 3, 1, -10])).toBe(600)
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})
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})
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