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added documentation, js standard style and jest testing to kadane algorithm file.
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function KadaneAlgo (array) {
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/* Kadane's algorithm is one of the most efficient ways to
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* calculate the maximum contiguos subarray sum for a given array.
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* Below is the implementation of kadanes's algorithm along with
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* some sample test cases.
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* There might be a special case in this problem if al the elements
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* of the given array are negative. In such a case, the maximum negative
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* value present in the array is the answer.
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*
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* Reference article :- https://www.geeksforgeeks.org/largest-sum-contiguous-subarray/
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*/
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function kadaneAlgo (array) {
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let cummulativeSum = 0
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let maxSum = 0
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let maxSum = Number.NEGATIVE_INFINITY // maxSum has the least posible value
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for (let i = 0; i < array.length; i++) {
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cummulativeSum = cummulativeSum + array[i]
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if (cummulativeSum < 0) {
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cummulativeSum = 0
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} else if (maxSum < cummulativeSum) {
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if (maxSum < cummulativeSum) {
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maxSum = cummulativeSum
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} else if (cummulativeSum < 0) {
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cummulativeSum = 0
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}
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}
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return maxSum
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// This function returns largest sum contiguous sum in a array
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}
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function main () {
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// input array
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const myArray = [1, 2, 3, 4, -6]
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const result = KadaneAlgo(myArray)
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// calling the function
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const result = kadaneAlgo(myArray)
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// result is the variable for storing the ourput of kadaneAlgo function
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console.log(result)
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}
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main()
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module.exports = { kadaneAlgo }
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8
Dynamic-Programming/tests/KadaneAlgo.test.js
Normal file
8
Dynamic-Programming/tests/KadaneAlgo.test.js
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const fc = require('../kadaneAlgo')
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test('test1', () => {
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expect(fc.kadaneAlgo([1, 2, 3, 4, 5])).toBe(15)
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})
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test('test2', () => {
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expect(fc.kadaneAlgo([-1, -2, -3, -4, 5])).toBe(5)
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})
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