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* refactor: NextSmallerElement * checkstyle: fix formatting * checkstyle: fix formatting * checkstyle: remove redundant new line --------- Co-authored-by: alxkm <alx@alx.com>
60 lines
1.9 KiB
Java
60 lines
1.9 KiB
Java
package com.thealgorithms.stacks;
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import java.util.Arrays;
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import java.util.Stack;
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/**
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* Utility class to find the next smaller element for each element in a given integer array.
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*
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* <p>The next smaller element for an element x is the first smaller element on the left side of x in the array.
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* If no such element exists, the result will contain -1 for that position.</p>
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*
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* <p>Example:</p>
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* <pre>
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* Input: {2, 7, 3, 5, 4, 6, 8}
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* Output: [-1, 2, 2, 3, 3, 4, 6]
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* </pre>
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*/
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public final class NextSmallerElement {
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private NextSmallerElement() {
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}
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/**
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* Finds the next smaller element for each element in the given array.
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*
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* @param array the input array of integers
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* @return an array where each element is replaced by the next smaller element on the left side in the input array,
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* or -1 if there is no smaller element.
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* @throws IllegalArgumentException if the input array is null
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*/
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public static int[] findNextSmallerElements(int[] array) {
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if (array == null) {
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throw new IllegalArgumentException("Input array cannot be null");
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}
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int[] result = new int[array.length];
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Stack<Integer> stack = new Stack<>();
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// Initialize all elements to -1 (in case there is no smaller element)
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Arrays.fill(result, -1);
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// Traverse the array from left to right
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for (int i = 0; i < array.length; i++) {
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// Maintain the stack such that the top of the stack is the next smaller element
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while (!stack.isEmpty() && stack.peek() >= array[i]) {
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stack.pop();
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}
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// If stack is not empty, then the top is the next smaller element
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if (!stack.isEmpty()) {
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result[i] = stack.peek();
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}
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// Push the current element onto the stack
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stack.push(array[i]);
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}
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return result;
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}
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}
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