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63 lines
1.9 KiB
Java
63 lines
1.9 KiB
Java
package com.thealgorithms.others;
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import java.util.Arrays;
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import java.util.Comparator;
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/**
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* The Line Sweep algorithm is used to solve range problems efficiently. It works by:
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* 1. Sorting a list of ranges by their start values in non-decreasing order.
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* 2. Sweeping through the number line (x-axis) while updating a count for each point based on the ranges.
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*
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* An overlapping range is defined as:
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* - (StartA <= EndB) AND (EndA >= StartB)
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*
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* References:
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* - https://en.wikipedia.org/wiki/Sweep_line_algorithm
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* - https://en.wikipedia.org/wiki/De_Morgan%27s_laws
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*/
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public final class LineSweep {
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private LineSweep() {
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}
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/**
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* Finds the maximum endpoint from a list of ranges.
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*
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* @param ranges a 2D array where each element is a range represented by [start, end]
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* @return the maximum endpoint among all ranges
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*/
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public static int findMaximumEndPoint(int[][] ranges) {
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Arrays.sort(ranges, Comparator.comparingInt(range -> range[1]));
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return ranges[ranges.length - 1][1];
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}
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/**
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* Determines if any of the given ranges overlap.
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*
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* @param ranges a 2D array where each element is a range represented by [start, end]
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* @return true if any ranges overlap, false otherwise
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*/
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public static boolean isOverlap(int[][] ranges) {
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if (ranges == null || ranges.length == 0) {
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return false;
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}
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int maximumEndPoint = findMaximumEndPoint(ranges);
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int[] numberLine = new int[maximumEndPoint + 2];
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for (int[] range : ranges) {
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int start = range[0];
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int end = range[1];
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numberLine[start] += 1;
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numberLine[end + 1] -= 1;
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}
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int currentCount = 0;
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int maxOverlaps = 0;
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for (int count : numberLine) {
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currentCount += count;
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maxOverlaps = Math.max(maxOverlaps, currentCount);
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}
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return maxOverlaps > 1;
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}
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}
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