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63 lines
2.1 KiB
Java
63 lines
2.1 KiB
Java
package com.thealgorithms.searches;
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import com.thealgorithms.devutils.searches.SearchAlgorithm;
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/**
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* The UpperBound method is used to return an index pointing to the first
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* element in the range [first, last) which has a value greater than val, or the
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* last index if no such element exists i.e. the index of the next smallest
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* number just greater than that number. If there are multiple values that are
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* equal to val it returns the index of the first such value.
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*
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* <p>
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* This is an extension of BinarySearch.
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*
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* <p>
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* Worst-case performance O(log n) Best-case performance O(1) Average
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* performance O(log n) Worst-case space complexity O(1)
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*
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* @author Pratik Padalia (https://github.com/15pratik)
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* @see SearchAlgorithm
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* @see BinarySearch
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*/
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class UpperBound implements SearchAlgorithm {
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/**
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* @param array is an array where the UpperBound value is to be found
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* @param key is an element for which the UpperBound is to be found
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* @param <T> is any comparable type
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* @return index of the UpperBound element
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*/
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@Override
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public <T extends Comparable<T>> int find(T[] array, T key) {
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return search(array, key, 0, array.length - 1);
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}
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/**
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* This method implements the Generic Binary Search
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*
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* @param array The array to make the binary search
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* @param key The number you are looking for
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* @param left The lower bound
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* @param right The upper bound
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* @return the location of the key
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*/
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private <T extends Comparable<T>> int search(T[] array, T key, int left, int right) {
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if (right <= left) {
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return left;
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}
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// find median
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int median = (left + right) >>> 1;
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int comp = key.compareTo(array[median]);
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if (comp < 0) {
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// key is smaller, median position can be a possible solution
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return search(array, key, left, median);
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} else {
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// key we are looking is greater, so we must look on the right of median position
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return search(array, key, median + 1, right);
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}
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}
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}
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