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* refactor: add JavaDocs and improve readability in InfixToPrefix * formatting: remove redundant newline --------- Co-authored-by: Deniz Altunkapan <93663085+DenizAltunkapan@users.noreply.github.com>
117 lines
4.3 KiB
Java
117 lines
4.3 KiB
Java
package com.thealgorithms.stacks;
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import java.util.Stack;
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import java.util.regex.Matcher;
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import java.util.regex.Pattern;
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/**
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* Utility class for converting an infix arithmetic expression
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* into its equivalent prefix notation expression.
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* <p>
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* This class provides a static method to perform the conversion,
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* validating balanced brackets before processing.
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* </p>
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*/
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public final class InfixToPrefix {
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private InfixToPrefix() {
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}
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/**
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* Converts a given infix expression string to a prefix expression string.
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* <p>
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* The method validates that the input expression has balanced brackets using
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* {@code BalancedBrackets.isBalanced} on the filtered bracket characters.
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* It throws an {@code IllegalArgumentException} if the brackets are unbalanced,
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* and a {@code NullPointerException} if the input is null.
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* </p>
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* <p>
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* Supported operators: {@code +, -, *, /, ^} and operands can be letters or digits.
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* </p>
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*
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* @param infixExpression the arithmetic expression in infix notation
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* @return the equivalent prefix notation expression
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* @throws IllegalArgumentException if brackets are unbalanced
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* @throws NullPointerException if the input expression is null
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*/
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public static String infix2Prefix(String infixExpression) {
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if (infixExpression == null) {
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throw new NullPointerException("Input expression cannot be null.");
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}
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infixExpression = infixExpression.trim();
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if (infixExpression.isEmpty()) {
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return "";
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}
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if (!BalancedBrackets.isBalanced(filterBrackets(infixExpression))) {
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throw new IllegalArgumentException("Invalid expression: unbalanced brackets.");
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}
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StringBuilder output = new StringBuilder();
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Stack<Character> operatorStack = new Stack<>();
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// Reverse the infix expression to facilitate prefix conversion
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String reversedInfix = new StringBuilder(infixExpression).reverse().toString();
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for (char token : reversedInfix.toCharArray()) {
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if (Character.isLetterOrDigit(token)) {
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// Append operands directly to output
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output.append(token);
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} else if (token == ')') {
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// Push ')' onto stack (since expression is reversed, '(' and ')' roles swapped)
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operatorStack.push(token);
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} else if (token == '(') {
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// Pop operators until ')' is found
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while (!operatorStack.isEmpty() && operatorStack.peek() != ')') {
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output.append(operatorStack.pop());
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}
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operatorStack.pop(); // Remove the ')'
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} else {
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// Pop operators with higher precedence before pushing current operator
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while (!operatorStack.isEmpty() && precedence(token) < precedence(operatorStack.peek())) {
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output.append(operatorStack.pop());
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}
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operatorStack.push(token);
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}
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}
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// Append any remaining operators in stack
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while (!operatorStack.isEmpty()) {
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output.append(operatorStack.pop());
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}
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// Reverse the output to obtain the final prefix expression
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return output.reverse().toString();
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}
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/**
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* Returns the precedence level of the given operator.
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*
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* @param operator the operator character (e.g., '+', '-', '*', '/', '^')
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* @return the precedence value: higher means higher precedence,
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* or -1 if the character is not a recognized operator
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*/
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private static int precedence(char operator) {
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return switch (operator) {
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case '+', '-' -> 0;
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case '*', '/' -> 1;
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case '^' -> 2;
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default -> -1;
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};
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}
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/**
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* Extracts only the bracket characters from the input string.
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* Supports parentheses (), curly braces {}, square brackets [], and angle brackets <>.
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*
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* @param input the original expression string
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* @return a string containing only bracket characters from the input
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*/
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private static String filterBrackets(String input) {
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Pattern pattern = Pattern.compile("[^(){}\\[\\]<>]");
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Matcher matcher = pattern.matcher(input);
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return matcher.replaceAll("");
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}
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}
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