package com.thealgorithms.searches; /** * Program to perform Saddleback Search Given a sorted 2D array(elements are * sorted across every row and column, assuming ascending order) of size n*m we * can search a given element in O(n+m) * *
* we start from bottom left corner if the current element is greater than the * given element then we move up else we move right Sample Input: 5 5 * ->Dimensions -10 -5 -3 4 9 -6 -2 0 5 10 -4 -1 1 6 12 2 3 7 8 13 100 120 130 * 140 150 140 ->element to be searched output: 4 3 // first value is row, * second one is column * * @author Nishita Aggarwal */ public final class SaddlebackSearch { private SaddlebackSearch() { } /** * This method performs Saddleback Search * * @param arr The **Sorted** array in which we will search the element. * @param row the current row. * @param col the current column. * @param key the element that we want to search for. * @throws IllegalArgumentException if the array is empty. * @return The index(row and column) of the element if found. Else returns * -1 -1. */ static int[] find(int[][] arr, int row, int col, int key) { if (arr.length == 0) { throw new IllegalArgumentException("Array is empty"); } // array to store the answer row and column int[] ans = {-1, -1}; if (row < 0 || col >= arr[row].length) { return ans; } if (arr[row][col] == key) { ans[0] = row; ans[1] = col; return ans; } // if the current element is greater than the given element then we move up else if (arr[row][col] > key) { return find(arr, row - 1, col, key); } // else we move right return find(arr, row, col + 1, key); } }