/** Author : SUBHAM SANGHAI A Dynamic Programming based solution for Edit Distance problem In Java Edit distance is a way of quantifying how dissimilar two strings (e.g., words) are to one another, by counting the minimum number of operations required to transform one string into the other **/ import java.util.HashMap; import java.util.Map; import java.util.Scanner; public class Edit_Distance { public static int minDistance(String word1, String word2) { int len1 = word1.length(); int len2 = word2.length(); // len1+1, len2+1, because finally return dp[len1][len2] int[][] dp = new int[len1 + 1][len2 + 1]; for (int i = 0; i <= len1; i++) { dp[i][0] = i; } for (int j = 0; j <= len2; j++) { dp[0][j] = j; } //iterate though, and check last char for (int i = 0; i < len1; i++) { char c1 = word1.charAt(i); for (int j = 0; j < len2; j++) { char c2 = word2.charAt(j); //if last two chars equal if (c1 == c2) { //update dp value for +1 length dp[i + 1][j + 1] = dp[i][j]; } else { int replace = dp[i][j] + 1; int insert = dp[i][j + 1] + 1; int delete = dp[i + 1][j] + 1; int min = replace > insert ? insert : replace; min = delete > min ? min : delete; dp[i + 1][j + 1] = min; } } } return dp[len1][len2]; } // Driver program to test above function public static void main(String args[]) { Scanner input = new Scanner(System.in); String s1,s2; System.out.println("Enter the First String"); s1 = input.nextLine(); System.out.println("Enter the Second String"); s2 = input.nextLine(); //ans stores the final Edit Distance between the two strings int ans=0; ans=minDistance(s1,s2); System.out.println("The minimum Edit Distance between \"" + s1 + "\" and \"" + s2 +"\" is "+ans); } }