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Add SRTF Algorithm (#5011)
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package com.thealgorithms.scheduling;
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import com.thealgorithms.devutils.entities.ProcessDetails;
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import java.util.ArrayList;
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import java.util.List;
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/**
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* Implementation of Shortest Remaining Time First Scheduling Algorithm.
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* In the SRTF scheduling algorithm, the process with the smallest amount of time remaining until completion is selected to execute.
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* Example:
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* Consider the processes p1, p2 and the following table with info about their arrival and burst time:
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* Process | Burst Time | Arrival Time
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* P1 | 6 ms | 0 ms
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* P2 | 2 ms | 1 ms
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* In this example, P1 will be executed at time = 0 until time = 1 when P2 arrives. At time = 2, P2 will be executed until time = 4. At time 4, P2 is done, and P1 is executed again to be done.
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* That's a simple example of how the algorithm works.
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* More information you can find here -> https://en.wikipedia.org/wiki/Shortest_remaining_time
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*/
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public class SRTFScheduling {
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protected List<ProcessDetails> processes;
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protected List<String> ready;
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/**
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* Constructor
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* @param processes ArrayList of ProcessDetails given as input
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*/
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public SRTFScheduling(ArrayList<ProcessDetails> processes) {
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this.processes = new ArrayList<>();
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ready = new ArrayList<>();
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this.processes = processes;
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}
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public void evaluateScheduling() {
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int time = 0, cr = 0; // cr=current running process, time= units of time
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int n = processes.size();
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int[] remainingTime = new int[n];
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/* calculating remaining time of every process and total units of time */
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for (int i = 0; i < n; i++) {
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remainingTime[i] = processes.get(i).getBurstTime();
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time += processes.get(i).getBurstTime();
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}
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/* if the first process doesn't arrive at 0, we have more units of time */
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if (processes.get(0).getArrivalTime() != 0) {
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time += processes.get(0).getArrivalTime();
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}
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/* printing id of the process which is executed at every unit of time */
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// if the first process doesn't arrive at 0, we print only \n until it arrives
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if (processes.get(0).getArrivalTime() != 0) {
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for (int i = 0; i < processes.get(0).getArrivalTime(); i++) {
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ready.add(null);
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}
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}
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for (int i = processes.get(0).getArrivalTime(); i < time; i++) {
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/* checking if there's a process with remaining time less than current running process.
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If we find it, then it executes. */
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for (int j = 0; j < n; j++) {
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if (processes.get(j).getArrivalTime() <= i && (remainingTime[j] < remainingTime[cr] && remainingTime[j] > 0 || remainingTime[cr] == 0)) {
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cr = j;
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}
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}
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ready.add(processes.get(cr).getProcessId());
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remainingTime[cr]--;
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}
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}
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}
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