Enhance docs, add more tests in TwosComplement (#5862)

This commit is contained in:
Hardik Pawar
2024-10-26 14:48:17 +05:30
committed by GitHub
parent ef7f2e97e3
commit fb85a4884f
2 changed files with 63 additions and 32 deletions

View File

@ -1,41 +1,62 @@
package com.thealgorithms.bitmanipulation;
/**
* @wikipedia - https://en.wikipedia.org/wiki/Two%27s_complement
* This Algorithm was first suggested by Jon Von Neumann
* @author - https://github.com/Monk-AbhinayVerma
* @return the two's complement of any binary number
* This class provides a method to compute the Two's Complement of a given binary number.
*
* <p>In two's complement representation, a binary number's negative value is obtained
* by taking the one's complement (inverting all bits) and then adding 1 to the result.
* This method handles both small and large binary strings and ensures the output is
* correct for all binary inputs, including edge cases like all zeroes and all ones.
*
* <p>For more information on Two's Complement:
* @see <a href="https://en.wikipedia.org/wiki/Two%27s_complement">Wikipedia - Two's Complement</a>
*
* <p>Algorithm originally suggested by Jon von Neumann.
*
* @author Abhinay Verma (https://github.com/Monk-AbhinayVerma)
*/
public final class TwosComplement {
private TwosComplement() {
}
// Function to get the 2's complement of a binary number
/**
* Computes the Two's Complement of the given binary string.
* Steps:
* 1. Compute the One's Complement (invert all bits).
* 2. Add 1 to the One's Complement to get the Two's Complement.
* 3. Iterate from the rightmost bit to the left, adding 1 and carrying over as needed.
* 4. If a carry is still present after the leftmost bit, prepend '1' to handle overflow.
*
* @param binary The binary number as a string (only '0' and '1' characters allowed).
* @return The two's complement of the input binary string as a new binary string.
* @throws IllegalArgumentException If the input contains non-binary characters.
*/
public static String twosComplement(String binary) {
StringBuilder onesComplement = new StringBuilder();
// Step 1: Find the 1's complement (invert the bits)
for (int i = 0; i < binary.length(); i++) {
if (binary.charAt(i) == '0') {
onesComplement.append('1');
} else {
onesComplement.append('0');
}
if (!binary.matches("[01]+")) {
throw new IllegalArgumentException("Input must contain only '0' and '1'.");
}
// Step 2: Add 1 to the 1's complement
StringBuilder onesComplement = new StringBuilder();
for (char bit : binary.toCharArray()) {
onesComplement.append(bit == '0' ? '1' : '0');
}
StringBuilder twosComplement = new StringBuilder(onesComplement);
boolean carry = true;
for (int i = onesComplement.length() - 1; i >= 0; i--) {
if (onesComplement.charAt(i) == '1' && carry) {
for (int i = onesComplement.length() - 1; i >= 0 && carry; i--) {
if (onesComplement.charAt(i) == '1') {
twosComplement.setCharAt(i, '0');
} else if (onesComplement.charAt(i) == '0' && carry) {
} else {
twosComplement.setCharAt(i, '1');
carry = false;
}
}
// If there is still a carry, append '1' at the beginning
if (carry) {
twosComplement.insert(0, '1');
}
return twosComplement.toString();
}
}