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Add tests for GenericRoot
(#4276)
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@ -4,27 +4,27 @@ package com.thealgorithms.maths;
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* Algorithm explanation:
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* https://technotip.com/6774/c-program-to-find-generic-root-of-a-number/#:~:text=Generic%20Root%3A%20of%20a%20number,get%20a%20single%2Ddigit%20output.&text=For%20Example%3A%20If%20user%20input,%2B%204%20%2B%205%20%3D%2015.
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*/
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public class GenericRoot {
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public static void main(String[] args) {
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int number1 = 1234;
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int number2 = 12345;
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int result1 = genericRoot(number1);
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int result2 = genericRoot(number2);
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System.out.println("Generic root of " + number1 + " is: " + result1);
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System.out.println("Generic root of " + number2 + " is: " + result2);
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public final class GenericRoot {
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private GenericRoot() {
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}
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private static int genericRoot(int n) {
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int root = 0;
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while (n > 0 || root > 9) {
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if (n == 0) {
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n = root;
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root = 0;
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}
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root += n % 10;
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n /= 10;
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private static int base = 10;
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private static int sumOfDigits(final int n) {
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assert n >= 0;
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if (n < base) {
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return n;
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}
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return root;
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return n % base + sumOfDigits(n / base);
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}
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public static int genericRoot(final int n) {
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if (n < 0) {
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return genericRoot(-n);
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}
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if (n > base) {
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return genericRoot(sumOfDigits(n));
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}
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return n;
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}
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}
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