refactor: MaximumSumOfDistinctSubarraysWithLengthK (#5433)

* refactor: MaximumSumOfDistinctSubarraysWithLengthK

* checkstyle: fix formatting

* checkstyle: fix formatting

* checkstyle: fix formatting

---------

Co-authored-by: alxkm <alx@alx.com>
This commit is contained in:
Alex Klymenko
2024-08-30 10:03:43 +02:00
committed by GitHub
parent cd38531b0d
commit c5b72816f3
2 changed files with 48 additions and 63 deletions

View File

@ -2,31 +2,21 @@ package com.thealgorithms.others;
import static org.junit.jupiter.api.Assertions.assertEquals;
import org.junit.jupiter.api.Test;
import java.util.stream.Stream;
import org.junit.jupiter.params.ParameterizedTest;
import org.junit.jupiter.params.provider.Arguments;
import org.junit.jupiter.params.provider.MethodSource;
public class MaximumSumOfDistinctSubarraysWithLengthKTest {
@Test
public void sampleTestCase1() {
assertEquals(15, MaximumSumOfDistinctSubarraysWithLengthK.maximumSubarraySum(3, 1, 5, 4, 2, 9, 9, 9));
@ParameterizedTest
@MethodSource("inputStream")
void testMaximumSubarraySum(int expected, int k, int[] arr) {
assertEquals(expected, MaximumSumOfDistinctSubarraysWithLengthK.maximumSubarraySum(k, arr));
}
@Test
public void sampleTestCase2() {
assertEquals(0, MaximumSumOfDistinctSubarraysWithLengthK.maximumSubarraySum(3, 4, 4, 4));
}
@Test
public void sampleTestCase3() {
assertEquals(12, MaximumSumOfDistinctSubarraysWithLengthK.maximumSubarraySum(3, 9, 9, 9, 1, 2, 3));
}
@Test
public void edgeCase1() {
assertEquals(0, MaximumSumOfDistinctSubarraysWithLengthK.maximumSubarraySum(0, 9, 9, 9));
}
@Test
public void edgeCase2() {
assertEquals(0, MaximumSumOfDistinctSubarraysWithLengthK.maximumSubarraySum(5, 9, 9, 9));
private static Stream<Arguments> inputStream() {
return Stream.of(Arguments.of(15, 3, new int[] {1, 5, 4, 2, 9, 9, 9}), Arguments.of(0, 3, new int[] {4, 4, 4}), Arguments.of(12, 3, new int[] {9, 9, 9, 1, 2, 3}), Arguments.of(0, 0, new int[] {9, 9, 9}), Arguments.of(0, 5, new int[] {9, 9, 9}), Arguments.of(9, 1, new int[] {9, 2, 3, 7}),
Arguments.of(15, 5, new int[] {1, 2, 3, 4, 5}), Arguments.of(6, 3, new int[] {-1, 2, 3, 1, -2, 4}), Arguments.of(10, 1, new int[] {10}), Arguments.of(0, 2, new int[] {7, 7, 7, 7}), Arguments.of(0, 3, new int[] {}), Arguments.of(0, 10, new int[] {1, 2, 3}));
}
}