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Add Javadoc comments (#4745)
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package com.thealgorithms.dynamicprogramming;
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package com.thealgorithms.dynamicprogramming;
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/**
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/**
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* A DynamicProgramming solution for Rod cutting problem Returns the best
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* A Dynamic Programming solution for the Rod cutting problem.
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* obtainable price for a rod of length n and price[] as prices of different
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* Returns the best obtainable price for a rod of length n and price[] as prices of different pieces.
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* pieces
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*/
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*/
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public class RodCutting {
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public class RodCutting {
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private static int cutRod(int[] price, int n) {
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/**
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* This method calculates the maximum obtainable value for cutting a rod of length n
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* into different pieces, given the prices for each possible piece length.
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*
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* @param price An array representing the prices of different pieces, where price[i-1]
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* represents the price of a piece of length i.
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* @param n The length of the rod to be cut.
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* @return The maximum obtainable value.
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*/
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public static int cutRod(int[] price, int n) {
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// Create an array to store the maximum obtainable values for each rod length.
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int[] val = new int[n + 1];
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int[] val = new int[n + 1];
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val[0] = 0;
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val[0] = 0;
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// Calculate the maximum value for each rod length from 1 to n.
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for (int i = 1; i <= n; i++) {
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for (int i = 1; i <= n; i++) {
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int max_val = Integer.MIN_VALUE;
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int maxVal = Integer.MIN_VALUE;
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for (int j = 0; j < i; j++) {
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// Try all possible ways to cut the rod and find the maximum value.
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max_val = Math.max(max_val, price[j] + val[i - j - 1]);
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for (int j = 1; j <= i; j++) {
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maxVal = Math.max(maxVal, price[j - 1] + val[i - j]);
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}
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}
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// Store the maximum value for the current rod length.
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val[i] = max_val;
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val[i] = maxVal;
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}
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}
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// The final element of 'val' contains the maximum obtainable value for a rod of length 'n'.
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return val[n];
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return val[n];
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}
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}
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// main function to test
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public static void main(String[] args) {
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int[] arr = new int[] {2, 5, 13, 19, 20};
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int result = cutRod(arr, arr.length);
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System.out.println("Maximum Obtainable Value is " + result);
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}
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}
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}
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