Add Longest Subarray With Sum Less Than or Equal to K algorithm (#6042)

src/main/java/com/thealgorithms/datastructures/trees/BinaryTree.java

@@ -144,7 +144,7 @@ public class BinaryTree {
             if (temp == root) {
                 root = null;
             } // This if/else assigns the new node to be either the left or right child of the
-              // parent
+            // parent
             else if (temp.parent.data < temp.data) {
                 temp.parent.right = null;
             } else {

src/main/java/com/thealgorithms/slidingwindow/LongestSubarrayWithSumLessOrEqualToK.java

@@ -0,0 +1,48 @@
+package com.thealgorithms.slidingwindow;
+
+/**
+ * The Longest Subarray with Sum Less Than or Equal to k algorithm finds the length
+ * of the longest subarray whose sum is less than or equal to a given value k.
+ *
+ * <p>
+ * Worst-case performance O(n)
+ * Best-case performance O(n)
+ * Average performance O(n)
+ * Worst-case space complexity O(1)
+ *
+ * @author https://github.com/Chiefpatwal
+ */
+public final class LongestSubarrayWithSumLessOrEqualToK {
+
+    // Prevent instantiation
+    private LongestSubarrayWithSumLessOrEqualToK() {
+    }
+
+    /**
+     * This method finds the length of the longest subarray with a sum less than or equal to k.
+     *
+     * @param arr is the input array
+     * @param k   is the maximum sum allowed
+     * @return the length of the longest subarray with sum less than or equal to k
+     */
+    public static int longestSubarrayWithSumLEK(int[] arr, int k) {
+        int maxLength = 0; // To store the maximum length found
+        int currentSum = 0; // To store the current sum of the window
+        int left = 0; // Left index of the sliding window
+
+        for (int right = 0; right < arr.length; right++) {
+            currentSum += arr[right]; // Expand the window to the right
+
+            // Shrink the window from the left if the current sum exceeds k
+            while (currentSum > k && left <= right) {
+                currentSum -= arr[left]; // Remove the leftmost element
+                left++; // Move the left index to the right
+            }
+
+            // Update maxLength if the current window is valid
+            maxLength = Math.max(maxLength, right - left + 1);
+        }
+
+        return maxLength; // Return the maximum length found
+    }
+}