Add Sliding Window algorithm and tests for maximum sum of subarray (#6001)

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PANKAJ PATWAL
2024-10-25 23:08:26 +05:30
committed by GitHub
parent 202879aa58
commit bc9645c0ea
2 changed files with 129 additions and 0 deletions

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package com.thealgorithms.slidingwindow;
/**
* The Sliding Window algorithm is used to find the maximum sum of a subarray
* of a fixed size k within a given array.
*
* <p>
* Worst-case performance O(n)
* Best-case performance O(n)
* Average performance O(n)
* Worst-case space complexity O(1)
*
* @author Your Name (https://github.com/Chiefpatwal)
*/
public final class MaxSumKSizeSubarray {
// Prevent instantiation
private MaxSumKSizeSubarray() {
}
/**
* This method finds the maximum sum of a subarray of a given size k.
*
* @param arr is the input array where the maximum sum needs to be found
* @param k is the size of the subarray
* @return the maximum sum of the subarray of size k
*/
public static int maxSumKSizeSubarray(int[] arr, int k) {
if (arr.length < k) {
return -1; // Edge case: not enough elements
}
int maxSum;
int windowSum = 0;
// Calculate the sum of the first window
for (int i = 0; i < k; i++) {
windowSum += arr[i];
}
maxSum = windowSum;
// Slide the window across the array
for (int i = k; i < arr.length; i++) {
windowSum += arr[i] - arr[i - k];
maxSum = Math.max(maxSum, windowSum);
}
return maxSum;
}
}

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package com.thealgorithms.slidingwindow;
import static org.junit.jupiter.api.Assertions.assertEquals;
import org.junit.jupiter.api.Test;
/**
* Unit tests for the MaxSumKSizeSubarray class.
*
* @author Your Name (https://github.com/Chiefpatwal)
*/
class MaxSumKSizeSubarrayTest {
/**
* Test for the basic case of finding the maximum sum.
*/
@Test
void testMaxSumKSizeSubarray() {
int[] arr = {1, 2, 3, 4, 5};
int k = 2;
int expectedMaxSum = 9; // 4 + 5
assertEquals(expectedMaxSum, MaxSumKSizeSubarray.maxSumKSizeSubarray(arr, k));
}
/**
* Test for a different array and subarray size.
*/
@Test
void testMaxSumKSizeSubarrayWithDifferentValues() {
int[] arr = {2, 1, 5, 1, 3, 2};
int k = 3;
int expectedMaxSum = 9; // 5 + 1 + 3
assertEquals(expectedMaxSum, MaxSumKSizeSubarray.maxSumKSizeSubarray(arr, k));
}
/**
* Test for edge case with insufficient elements.
*/
@Test
void testMaxSumKSizeSubarrayWithInsufficientElements() {
int[] arr = {1, 2};
int k = 3; // Not enough elements
int expectedMaxSum = -1; // Edge case
assertEquals(expectedMaxSum, MaxSumKSizeSubarray.maxSumKSizeSubarray(arr, k));
}
/**
* Test for large array.
*/
@Test
void testMaxSumKSizeSubarrayWithLargeArray() {
int[] arr = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10};
int k = 5;
int expectedMaxSum = 40; // 6 + 7 + 8 + 9 + 10
assertEquals(expectedMaxSum, MaxSumKSizeSubarray.maxSumKSizeSubarray(arr, k));
}
/**
* Test for array with negative numbers.
*/
@Test
void testMaxSumKSizeSubarrayWithNegativeNumbers() {
int[] arr = {-1, -2, -3, -4, -5};
int k = 2;
int expectedMaxSum = -3; // -1 + -2
assertEquals(expectedMaxSum, MaxSumKSizeSubarray.maxSumKSizeSubarray(arr, k));
}
/**
* Test for the case where k equals the array length.
*/
@Test
void testMaxSumKSizeSubarrayWithKEqualToArrayLength() {
int[] arr = {1, 2, 3, 4, 5};
int k = 5;
int expectedMaxSum = 15; // 1 + 2 + 3 + 4 + 5
assertEquals(expectedMaxSum, MaxSumKSizeSubarray.maxSumKSizeSubarray(arr, k));
}
}