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update BalancedBrackets
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@ -1,10 +1,8 @@
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package data_structures.Stacks;
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package DataStructures.Stacks;
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import java.util.Scanner;
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import java.util.Stack;
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import java.util.Stack;
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/**
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/**
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*
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* The nested brackets problem is a problem that determines if a sequence of
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* The nested brackets problem is a problem that determines if a sequence of
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* brackets are properly nested. A sequence of brackets s is considered properly
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* brackets are properly nested. A sequence of brackets s is considered properly
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* nested if any of the following conditions are true: - s is empty - s has the
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* nested if any of the following conditions are true: - s is empty - s has the
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@ -15,71 +13,69 @@ import java.util.Stack;
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* returns true if S is nested and false otherwise.
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* returns true if S is nested and false otherwise.
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*
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*
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* @author akshay sharma
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* @author akshay sharma
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* @date: 2017-10-17
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* @author <a href="https://github.com/khalil2535">khalil2535<a>
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* @author <a href="https://github.com/khalil2535">khalil2535<a>
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*
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* @author shellhub
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*/
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*/
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class BalancedBrackets {
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class BalancedBrackets {
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/**
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/**
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* Check if {@code leftBracket} and {@code rightBracket} is paired or not
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*
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*
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* @param s
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* @param leftBracket left bracket
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* @return
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* @param rightBracket right bracket
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* @return {@code true} if {@code leftBracket} and {@code rightBracket} is paired,
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* otherwise {@code false}
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*/
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*/
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static boolean is_balanced(String s) {
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public static boolean isPaired(char leftBracket, char rightBracket) {
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Stack<Character> bracketsStack = new Stack<>();
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char[][] pairedBrackets = {
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char[] text = s.toCharArray();
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{'(', ')'},
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for (char x : text) {
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{'[', ']'},
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switch (x) {
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{'{', '}'},
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case '{':
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{'<', '>'}
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case '<':
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};
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case '(':
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for (char[] pairedBracket : pairedBrackets) {
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case '[':
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if (pairedBracket[0] == leftBracket && pairedBracket[1] == rightBracket) {
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bracketsStack.push(x);
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return true;
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break;
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case '}':
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if (!bracketsStack.empty() && bracketsStack.pop() == '{') {
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break;
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} else {
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return false;
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}
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case '>':
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if (!bracketsStack.empty() && bracketsStack.pop() == '<') {
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break;
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} else {
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return false;
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}
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case ')':
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if (!bracketsStack.empty() && bracketsStack.pop() == '(') {
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break;
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} else {
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return false;
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}
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case ']':
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if (!bracketsStack.empty() && bracketsStack.pop() == '[') {
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break;
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} else {
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return false;
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}
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}
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}
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}
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}
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return bracketsStack.empty();
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return false;
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}
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}
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/**
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/**
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* Check if {@code brackets} is balanced
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*
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*
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* @param args
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* @param brackets the brackets
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* @TODO remove main method and Test using JUnit or other methodology
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* @return {@code true} if {@code brackets} is balanced, otherwise {@code false}
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*/
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*/
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public static void main(String args[]) {
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public static boolean isBalanced(String brackets) {
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try (Scanner in = new Scanner(System.in)) {
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if (brackets == null) {
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System.out.println("Enter sequence of brackets: ");
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throw new IllegalArgumentException("brackets is null");
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String s = in.nextLine();
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}
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if (is_balanced(s)) {
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Stack<Character> bracketsStack = new Stack<>();
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System.out.println(s + " is balanced");
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for (char bracket : brackets.toCharArray()) {
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} else {
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switch (bracket) {
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System.out.println(s + " ain't balanced");
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case '(':
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case '[':
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case '{':
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bracketsStack.push(bracket);
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break;
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case ')':
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case ']':
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case '}':
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if (!(!bracketsStack.isEmpty() && isPaired(bracketsStack.pop(), bracket))) {
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return false;
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}
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break;
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default: /* other character is invalid */
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return false;
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}
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}
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}
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}
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return bracketsStack.isEmpty();
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}
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public static void main(String[] args) {
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assert isBalanced("[()]{}{[()()]()}");
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assert !isBalanced("[(])");
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}
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}
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}
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}
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