Enhance docs, add tests in Intersection (#5976)

This commit is contained in:
Hardik Pawar
2024-10-26 21:38:52 +05:30
committed by GitHub
parent 26f114cb60
commit 84cd883e95
3 changed files with 113 additions and 6 deletions

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@ -858,6 +858,7 @@
* [GenericHashMapUsingArrayListTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/hashmap/hashing/GenericHashMapUsingArrayListTest.java)
* [GenericHashMapUsingArrayTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/hashmap/hashing/GenericHashMapUsingArrayTest.java)
* [HashMapTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/hashmap/hashing/HashMapTest.java)
* [IntersectionTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/hashmap/hashing/IntersectionTest.java)
* [LinearProbingHashMapTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/hashmap/hashing/LinearProbingHashMapTest.java)
* [MajorityElementTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/hashmap/hashing/MajorityElementTest.java)
* [MapTest](https://github.com/TheAlgorithms/Java/blob/master/src/test/java/com/thealgorithms/datastructures/hashmap/hashing/MapTest.java)

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package com.thealgorithms.datastructures.hashmap.hashing;
/*
* this is algo which implies common mathematical set theory concept
* called intersection in which result is common values of both the sets
* here metaphor of sets is HashMap
*/
import java.util.ArrayList;
import java.util.Collections;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
/**
* The {@code Intersection} class provides a method to compute the intersection of two integer arrays.
* The intersection is defined as the set of common elements present in both arrays.
* <p>
* This class utilizes a HashMap to efficiently count occurrences of elements in the first array,
* allowing for an efficient lookup of common elements in the second array.
* </p>
*
* <p>
* Example:
* <pre>
* int[] array1 = {1, 2, 2, 1};
* int[] array2 = {2, 2};
* List<Integer> result = Intersection.intersection(array1, array2); // result will contain [2, 2]
* </pre>
* </p>
*
* <p>
* Note: The order of the returned list may vary since it depends on the order of elements
* in the input arrays.
* </p>
*/
public final class Intersection {
/**
* Computes the intersection of two integer arrays.
* Steps:
* 1. Count the occurrences of each element in the first array using a HashMap.
* 2. Iterate over the second array and check if the element is present in the HashMap.
* If it is, add it to the result list and decrement the count in the HashMap.
* 3. Return the result list containing the intersection of the two arrays.
*
* @param arr1 the first array of integers
* @param arr2 the second array of integers
* @return a list containing the intersection of the two arrays, or an empty list if either array is null or empty
*/
public static List<Integer> intersection(int[] arr1, int[] arr2) {
if (arr1 == null || arr2 == null || arr1.length == 0 || arr2.length == 0) {
return Collections.emptyList();
}
Map<Integer, Integer> cnt = new HashMap<>(16);
for (int v : arr1) {
cnt.put(v, cnt.getOrDefault(v, 0) + 1);
}
List<Integer> res = new ArrayList<>();
for (int v : arr2) {
if (cnt.containsKey(v) && cnt.get(v) > 0) {

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package com.thealgorithms.datastructures.hashmap.hashing;
import static org.junit.jupiter.api.Assertions.assertEquals;
import static org.junit.jupiter.api.Assertions.assertTrue;
import java.util.List;
import org.junit.jupiter.api.Test;
public class IntersectionTest {
@Test
void testBasicIntersection() {
int[] arr1 = {1, 2, 2, 1};
int[] arr2 = {2, 2};
List<Integer> result = Intersection.intersection(arr1, arr2);
assertEquals(List.of(2, 2), result, "Intersection should return [2, 2]");
}
@Test
void testNoIntersection() {
int[] arr1 = {1, 2, 3};
int[] arr2 = {4, 5, 6};
List<Integer> result = Intersection.intersection(arr1, arr2);
assertTrue(result.isEmpty(), "Intersection should be empty for disjoint sets");
}
@Test
void testEmptyArray() {
int[] arr1 = {};
int[] arr2 = {1, 2, 3};
List<Integer> result = Intersection.intersection(arr1, arr2);
assertTrue(result.isEmpty(), "Intersection should be empty when first array is empty");
result = Intersection.intersection(arr2, arr1);
assertTrue(result.isEmpty(), "Intersection should be empty when second array is empty");
}
@Test
void testNullArray() {
int[] arr1 = null;
int[] arr2 = {1, 2, 3};
List<Integer> result = Intersection.intersection(arr1, arr2);
assertTrue(result.isEmpty(), "Intersection should be empty when first array is null");
result = Intersection.intersection(arr2, arr1);
assertTrue(result.isEmpty(), "Intersection should be empty when second array is null");
}
@Test
void testMultipleOccurrences() {
int[] arr1 = {5, 5, 5, 6};
int[] arr2 = {5, 5, 6, 6, 6};
List<Integer> result = Intersection.intersection(arr1, arr2);
assertEquals(List.of(5, 5, 6), result, "Intersection should return [5, 5, 6]");
}
@Test
void testSameElements() {
int[] arr1 = {1, 1, 1};
int[] arr2 = {1, 1, 1};
List<Integer> result = Intersection.intersection(arr1, arr2);
assertEquals(List.of(1, 1, 1), result, "Intersection should return [1, 1, 1] for same elements");
}
@Test
void testLargeArrays() {
int[] arr1 = new int[1000];
int[] arr2 = new int[1000];
for (int i = 0; i < 1000; i++) {
arr1[i] = i;
arr2[i] = i;
}
List<Integer> result = Intersection.intersection(arr1, arr2);
assertEquals(1000, result.size(), "Intersection should return all elements for identical large arrays");
}
}