diff --git a/DynamicProgramming/DiceThrow.java b/DynamicProgramming/DiceThrow.java
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+// Given N dice each with M faces, numbered from 1 to M, find the number of ways to get sum X.
+// X is the summation of values on each face when all the dice are thrown.
+
+/* The Naive approach is to find all the possible combinations of values from n dice and
+keep on counting the results that sum to X. This can be done using recursion. */
+
+// The above recursion solution exhibits overlapping subproblems.
+
+/* Hence, storing the results of the solved sub-problems saves time.
+And it can be done using Dynamic Programming(DP).
+Following is implementation of Dynamic Programming approach. */
+
+
+// Code ---->
+// Java program to find number of ways to get sum 'x' with 'n' 
+// dice where every dice has 'm' faces 
+import java.util.*;
+import java.lang.*;
+import java.io.*;
+
+class DP {
+    /* The main function that returns the number of ways to get sum 'x' with 'n' dice and 'm' with m faces. */
+    public static long findWays(int m, int n, int x){
+      
+    /* Create a table to store the results of subproblems. 
+    One extra row and column are used for simplicity 
+    (Number of dice is directly used as row index and sum is directly used as column index). 
+    The entries in 0th row and 0th column are never used. */
+    long[][] table = new long[n+1][x+1];
+        
+    /* Table entries for only one dice */
+    for(int j = 1; j <= m && j <= x; j++)
+                table[1][j] = 1;
+            
+    /* Fill rest of the entries in table using recursive relation 
+    i: number of dice, j: sum */
+    for(int i = 2; i <= n;i ++){
+                for(int j = 1; j <= x; j++){
+                    for(int k = 1; k < j && k <= m; k++)
+                        table[i][j] += table[i-1][j-k];
+                }
+        }
+        
+        return table[n][x];
+    }
+    
+    public static void main (String[] args) {
+        System.out.println(findWays(4, 2, 1)); 
+        System.out.println(findWays(2, 2, 3)); 
+        System.out.println(findWays(6, 3, 8)); 
+        System.out.println(findWays(4, 2, 5)); 
+        System.out.println(findWays(4, 3, 5)); 
+    }
+}
+
+/*
+OUTPUT:
+0
+2
+21
+4
+6
+*/
+
+// Time Complexity: O(m * n * x) where m is number of faces, n is number of dice and x is given sum.
+