Add BandwidthAllocation algorithm (#5807)

src/main/java/com/thealgorithms/greedyalgorithms/BandwidthAllocation.java

@@ -0,0 +1,58 @@
+package com.thealgorithms.greedyalgorithms;
+
+import java.util.Arrays;
+
+/**
+ * Class to solve the Bandwidth Allocation Problem.
+ * The goal is to maximize the value gained by allocating bandwidth to users.
+ * Example:
+ * Bandwidth = 10
+ * Users = [3, 5, 7]
+ * Values = [10, 20, 30]
+ * The maximum value achievable is 40 by allocating 3 units to user 0 and 7 units to user 2.
+ *
+ * @author Hardvan
+ */
+public final class BandwidthAllocation {
+    private BandwidthAllocation() {
+    }
+
+    /**
+     * Allocates bandwidth to maximize value.
+     * Steps:
+     * 1. Calculate the ratio of value/demand for each user.
+     * 2. Sort the users in descending order of the ratio.
+     * 3. Allocate bandwidth to users in order of the sorted list.
+     * 4. If the bandwidth is not enough to allocate the full demand of a user, allocate a fraction of the demand.
+     * 5. Return the maximum value achievable.
+     *
+     * @param bandwidth total available bandwidth to allocate
+     * @param users     array of user demands
+     * @param values    array of values associated with each user's demand
+     * @return the maximum value achievable
+     */
+    public static int maxValue(int bandwidth, int[] users, int[] values) {
+        int n = users.length;
+        double[][] ratio = new double[n][2]; // {index, ratio}
+
+        for (int i = 0; i < n; i++) {
+            ratio[i][0] = i;
+            ratio[i][1] = (double) values[i] / users[i];
+        }
+
+        Arrays.sort(ratio, (a, b) -> Double.compare(b[1], a[1]));
+
+        int maxValue = 0;
+        for (int i = 0; i < n; i++) {
+            int index = (int) ratio[i][0];
+            if (bandwidth >= users[index]) {
+                maxValue += values[index];
+                bandwidth -= users[index];
+            } else {
+                maxValue += (int) (ratio[i][1] * bandwidth);
+                break;
+            }
+        }
+        return maxValue;
+    }
+}