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docs(DP): update EggDropping.java

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Libin Yang
2019-02-23 21:06:32 +08:00
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parent 09d5cb01f3
commit 6ff87322e6
1 changed files with 46 additions and 52 deletions
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Dynamic Programming/EggDropping.java
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@ -1,53 +1,47 @@
//Dynamic Programming solution for the Egg Dropping Puzzle /**
public class EggDropping * Dynamic Programming solution for the Egg Dropping Puzzle
{ */
public class EggDropping {
// min trials with n eggs and m floors // min trials with n eggs and m floors
private static int minTrials(int n, int m) private static int minTrials(int n, int m) {
{
int eggFloor[][] = new int[n+1][m+1]; int[][] eggFloor = new int[n + 1][m + 1];
int result, x; int result, x;
for (int i = 1; i <= n; i++) for (int i = 1; i <= n; i++) {
{ eggFloor[i][0] = 0; // Zero trial for zero floor.
eggFloor[i][0] = 0; // Zero trial for zero floor. eggFloor[i][1] = 1; // One trial for one floor
eggFloor[i][1] = 1; // One trial for one floor }
}
// j trials for only 1 egg // j trials for only 1 egg
for (int j = 1; j <= m; j++) for (int j = 1; j <= m; j++)
eggFloor[1][j] = j; eggFloor[1][j] = j;
// Using bottom-up approach in DP // Using bottom-up approach in DP
for (int i = 2; i <= n; i++) for (int i = 2; i <= n; i++) {
{ for (int j = 2; j <= m; j++) {
for (int j = 2; j <= m; j++) eggFloor[i][j] = Integer.MAX_VALUE;
{ for (x = 1; x <= j; x++) {
eggFloor[i][j] = Integer.MAX_VALUE; result = 1 + Math.max(eggFloor[i - 1][x - 1], eggFloor[i][j - x]);
for (x = 1; x <= j; x++)
{
result = 1 + Math.max(eggFloor[i-1][x-1], eggFloor[i][j-x]);
//choose min of all values for particular x // choose min of all values for particular x
if (result < eggFloor[i][j]) if (result < eggFloor[i][j])
eggFloor[i][j] = result; eggFloor[i][j] = result;
} }
} }
} }
return eggFloor[n][m]; return eggFloor[n][m];
} }
//testing program public static void main(String args[]) {
public static void main(String args[]) int n = 2, m = 4;
{ // result outputs min no. of trials in worst case for n eggs and m floors
int n = 2, m = 4; int result = minTrials(n, m);
//result outputs min no. of trials in worst case for n eggs and m floors System.out.println(result);
int result = minTrials(n, m); }
System.out.println(result);
}
} }