Add automatic linter (#4214)

This commit is contained in:
acbin
2023-06-09 20:05:14 +08:00
committed by GitHub
parent 00282efd8b
commit 415a04ea7f
188 changed files with 661 additions and 1133 deletions

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@ -24,8 +24,7 @@ public class BoundaryFill {
* @param x_co_ordinate The x co-ordinate at which color is to be filled
* @param y_co_ordinate The y co-ordinate at which color is to be filled
*/
public static void putPixel(
int[][] image, int x_co_ordinate, int y_co_ordinate, int new_color) {
public static void putPixel(int[][] image, int x_co_ordinate, int y_co_ordinate, int new_color) {
image[x_co_ordinate][y_co_ordinate] = new_color;
}
@ -38,11 +37,8 @@ public class BoundaryFill {
* @param new_color The new color which to be filled in the image
* @param boundary_color The old color which is to be replaced in the image
*/
public static void boundaryFill(
int[][] image, int x_co_ordinate, int y_co_ordinate, int new_color, int boundary_color) {
if (x_co_ordinate >= 0 && y_co_ordinate >= 0
&& getPixel(image, x_co_ordinate, y_co_ordinate) != new_color
&& getPixel(image, x_co_ordinate, y_co_ordinate) != boundary_color) {
public static void boundaryFill(int[][] image, int x_co_ordinate, int y_co_ordinate, int new_color, int boundary_color) {
if (x_co_ordinate >= 0 && y_co_ordinate >= 0 && getPixel(image, x_co_ordinate, y_co_ordinate) != new_color && getPixel(image, x_co_ordinate, y_co_ordinate) != boundary_color) {
putPixel(image, x_co_ordinate, y_co_ordinate, new_color);
boundaryFill(image, x_co_ordinate + 1, y_co_ordinate, new_color, boundary_color);
boundaryFill(image, x_co_ordinate - 1, y_co_ordinate, new_color, boundary_color);

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@ -22,8 +22,7 @@ public class BruteForceKnapsack {
// (1) nth item included
// (2) not included
else {
return Math.max(
val[n - 1] + knapSack(W - wt[n - 1], wt, val, n - 1), knapSack(W, wt, val, n - 1));
return Math.max(val[n - 1] + knapSack(W - wt[n - 1], wt, val, n - 1), knapSack(W, wt, val, n - 1));
}
}

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@ -10,10 +10,8 @@ public class CoinChange {
int amount = 12;
int[] coins = {2, 4, 5};
System.out.println("Number of combinations of getting change for " + amount
+ " is: " + change(coins, amount));
System.out.println("Minimum number of coins required for amount :" + amount
+ " is: " + minimumCoins(coins, amount));
System.out.println("Number of combinations of getting change for " + amount + " is: " + change(coins, amount));
System.out.println("Minimum number of coins required for amount :" + amount + " is: " + minimumCoins(coins, amount));
}
/**

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@ -76,8 +76,7 @@ public class EditDistance {
s2 = input.nextLine();
// ans stores the final Edit Distance between the two strings
int ans = minDistance(s1, s2);
System.out.println(
"The minimum Edit Distance between \"" + s1 + "\" and \"" + s2 + "\" is " + ans);
System.out.println("The minimum Edit Distance between \"" + s1 + "\" and \"" + s2 + "\" is " + ans);
input.close();
}

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@ -25,8 +25,7 @@ public class KnapsackMemoization {
}
// Returns the value of maximum profit using recursive approach
int solveKnapsackRecursive(
int capacity, int[] weights, int[] profits, int numOfItems, int[][] dpTable) {
int solveKnapsackRecursive(int capacity, int[] weights, int[] profits, int numOfItems, int[][] dpTable) {
// Base condition
if (numOfItems == 0 || capacity == 0) {
return 0;
@ -38,16 +37,11 @@ public class KnapsackMemoization {
if (weights[numOfItems - 1] > capacity) {
// Store the value of function call stack in table
dpTable[numOfItems][capacity]
= solveKnapsackRecursive(capacity, weights, profits, numOfItems - 1, dpTable);
dpTable[numOfItems][capacity] = solveKnapsackRecursive(capacity, weights, profits, numOfItems - 1, dpTable);
return dpTable[numOfItems][capacity];
} else {
// Return value of table after storing
return dpTable[numOfItems][capacity]
= Math.max((profits[numOfItems - 1]
+ solveKnapsackRecursive(capacity - weights[numOfItems - 1], weights,
profits, numOfItems - 1, dpTable)),
solveKnapsackRecursive(capacity, weights, profits, numOfItems - 1, dpTable));
return dpTable[numOfItems][capacity] = Math.max((profits[numOfItems - 1] + solveKnapsackRecursive(capacity - weights[numOfItems - 1], weights, profits, numOfItems - 1, dpTable)), solveKnapsackRecursive(capacity, weights, profits, numOfItems - 1, dpTable));
}
}
}

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@ -32,9 +32,7 @@ public class LevenshteinDistance {
if (str1.charAt(i - 1) == str2.charAt(j - 1)) {
distanceMat[i][j] = distanceMat[i - 1][j - 1];
} else {
distanceMat[i][j] = 1
+ minimum(distanceMat[i - 1][j], distanceMat[i - 1][j - 1],
distanceMat[i][j - 1]);
distanceMat[i][j] = 1 + minimum(distanceMat[i - 1][j], distanceMat[i - 1][j - 1], distanceMat[i][j - 1]);
}
}
}

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@ -32,8 +32,7 @@ public class LongestPalindromicSubsequence {
} else {
// if the last chars match, then remove it from both strings and recur
if (original.charAt(original.length() - 1) == reverse.charAt(reverse.length() - 1)) {
String bestSubResult = recursiveLPS(original.substring(0, original.length() - 1),
reverse.substring(0, reverse.length() - 1));
String bestSubResult = recursiveLPS(original.substring(0, original.length() - 1), reverse.substring(0, reverse.length() - 1));
bestResult = reverse.charAt(reverse.length() - 1) + bestSubResult;
} else {
@ -42,10 +41,8 @@ public class LongestPalindromicSubsequence {
// updated original and reverse again then select the best result from these two
// subproblems.
String bestSubResult1
= recursiveLPS(original, reverse.substring(0, reverse.length() - 1));
String bestSubResult2
= recursiveLPS(original.substring(0, original.length() - 1), reverse);
String bestSubResult1 = recursiveLPS(original, reverse.substring(0, reverse.length() - 1));
String bestSubResult2 = recursiveLPS(original.substring(0, original.length() - 1), reverse);
if (bestSubResult1.length() > bestSubResult2.length()) {
bestResult = bestSubResult1;
} else {

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@ -28,8 +28,7 @@ public class MatrixChainRecursiveTopDownMemoisation {
return m[i][j];
} else {
for (int k = i; k < j; k++) {
int q = Lookup_Chain(m, p, i, k) + Lookup_Chain(m, p, k + 1, j)
+ (p[i - 1] * p[k] * p[j]);
int q = Lookup_Chain(m, p, i, k) + Lookup_Chain(m, p, k + 1, j) + (p[i - 1] * p[k] * p[j]);
if (q < m[i][j]) {
m[i][j] = q;
}

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@ -25,8 +25,7 @@ public class OptimalJobScheduling {
* @param Transfer ,M*M symmetric matrix refers to the transportation delay for each pair of
* machines
*/
public OptimalJobScheduling(
int numberProcesses, int numberMachines, int[][] Run, int[][] Transfer) {
public OptimalJobScheduling(int numberProcesses, int numberMachines, int[][] Run, int[][] Transfer) {
this.numberProcesses = numberProcesses;
this.numberMachines = numberMachines;
this.Run = Run;
@ -75,15 +74,13 @@ public class OptimalJobScheduling {
return Run[process][machine];
else {
int[] runningCosts
= new int[numberMachines]; // stores the costs of executing our Process depending on
// the Machine the previous one was executed
int[] runningCosts = new int[numberMachines]; // stores the costs of executing our Process depending on
// the Machine the previous one was executed
for (int k = 0; k < numberMachines; k++) // computes the cost of executing the previous
// process to each and every Machine
runningCosts[k] = Cost[process - 1][k] + Transfer[k][machine]
+ Run[process][machine]; // transferring the result to our Machine and executing
// the Process to our Machine
runningCosts[k] = Cost[process - 1][k] + Transfer[k][machine] + Run[process][machine]; // transferring the result to our Machine and executing
// the Process to our Machine
return findMin(runningCosts); // returns the minimum running cost
}

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@ -49,8 +49,7 @@ public class PalindromicPartitioning {
if (L == 2) {
isPalindrome[i][j] = (word.charAt(i) == word.charAt(j));
} else {
isPalindrome[i][j]
= (word.charAt(i) == word.charAt(j)) && isPalindrome[i + 1][j - 1];
isPalindrome[i][j] = (word.charAt(i) == word.charAt(j)) && isPalindrome[i + 1][j - 1];
}
}
}
@ -81,8 +80,7 @@ public class PalindromicPartitioning {
word = input.nextLine();
// ans stores the final minimal cut count needed for partitioning
int ans = minimalpartitions(word);
System.out.println(
"The minimum cuts needed to partition \"" + word + "\" into palindromes is " + ans);
System.out.println("The minimum cuts needed to partition \"" + word + "\" into palindromes is " + ans);
input.close();
}
}

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@ -159,8 +159,7 @@ public class RegexMatching {
String pat = "*";
System.out.println("Method 1: " + regexRecursion(src, pat));
System.out.println("Method 2: " + regexRecursion(src, pat, 0, 0));
System.out.println(
"Method 3: " + regexRecursion(src, pat, 0, 0, new int[src.length()][pat.length()]));
System.out.println("Method 3: " + regexRecursion(src, pat, 0, 0, new int[src.length()][pat.length()]));
System.out.println("Method 4: " + regexBU(src, pat));
}
}

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@ -75,8 +75,7 @@ public class WineProblem {
public static void main(String[] args) {
int[] arr = {2, 3, 5, 1, 4};
System.out.println("Method 1: " + WPRecursion(arr, 0, arr.length - 1));
System.out.println(
"Method 2: " + WPTD(arr, 0, arr.length - 1, new int[arr.length][arr.length]));
System.out.println("Method 2: " + WPTD(arr, 0, arr.length - 1, new int[arr.length][arr.length]));
System.out.println("Method 3: " + WPBU(arr));
}
}