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Add AssignmentUsingBitmask
algorithm (#5792)
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package com.thealgorithms.dynamicprogramming;
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import java.util.ArrayList;
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import java.util.Arrays;
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import java.util.List;
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/**
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* The AssignmentUsingBitmask class is used to calculate the total number of ways
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* tasks can be distributed among people, given specific constraints on who can perform which tasks.
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* The approach uses bitmasking and dynamic programming to efficiently solve the problem.
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*
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* @author Hardvan
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*/
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public final class AssignmentUsingBitmask {
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private final int totalTasks;
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private final int[][] dp;
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private final List<List<Integer>> task;
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private final int finalMask;
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/**
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* Constructor for the AssignmentUsingBitmask class.
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*
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* @param taskPerformed a list of lists, where each inner list contains the tasks that a person can perform.
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* @param total the total number of tasks.
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*/
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public AssignmentUsingBitmask(List<List<Integer>> taskPerformed, int total) {
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this.totalTasks = total;
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this.dp = new int[1 << taskPerformed.size()][total + 1];
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for (int[] row : dp) {
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Arrays.fill(row, -1);
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}
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this.task = new ArrayList<>(totalTasks + 1);
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for (int i = 0; i <= totalTasks; i++) {
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this.task.add(new ArrayList<>());
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}
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// Final mask to check if all persons are included
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this.finalMask = (1 << taskPerformed.size()) - 1;
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// Fill the task list
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for (int i = 0; i < taskPerformed.size(); i++) {
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for (int j : taskPerformed.get(i)) {
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this.task.get(j).add(i);
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}
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}
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}
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/**
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* Counts the ways to assign tasks until the given task number with the specified mask.
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*
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* @param mask the bitmask representing the current state of assignments.
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* @param taskNo the current task number being processed.
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* @return the number of ways to assign tasks.
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*/
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private int countWaysUntil(int mask, int taskNo) {
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if (mask == finalMask) {
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return 1;
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}
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if (taskNo > totalTasks) {
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return 0;
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}
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if (dp[mask][taskNo] != -1) {
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return dp[mask][taskNo];
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}
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int totalWays = countWaysUntil(mask, taskNo + 1);
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// Assign tasks to all possible persons
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for (int p : task.get(taskNo)) {
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// If the person is already assigned a task
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if ((mask & (1 << p)) != 0) {
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continue;
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}
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totalWays += countWaysUntil(mask | (1 << p), taskNo + 1);
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}
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dp[mask][taskNo] = totalWays;
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return dp[mask][taskNo];
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}
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/**
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* Counts the total number of ways to distribute tasks among persons.
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*
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* @return the total number of ways to distribute tasks.
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*/
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public int countNoOfWays() {
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return countWaysUntil(0, 1);
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}
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}
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