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Moved StackPostfixNotation.java from the Others section to the Stack section (#4372)
* Moved StackPostfixNotation.java from the Others section to the Stack section * Put all stack related algo in a separate stack directory in the algorithms directory. The stack directory under data-structures now only contains various implementations of the stack data structure. * formatted files
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package com.thealgorithms.stacks;
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import java.util.Arrays;
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import java.util.Stack;
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/*
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Given an array "input" you need to print the first smaller element for each element to the left
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side of an array. For a given element x of an array, the Next Smaller element of that element is
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the first smaller element to the left side of it. If no such element is present print -1.
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Example
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input = { 2, 7, 3, 5, 4, 6, 8 };
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At i = 0
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No elements to left of it : -1
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At i = 1
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Next smaller element between (0 , 0) is 2
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At i = 2
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Next smaller element between (0 , 1) is 2
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At i = 3
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Next smaller element between (0 , 2) is 3
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At i = 4
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Next smaller element between (0 , 3) is 3
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At i = 5
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Next smaller element between (0 , 4) is 4
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At i = 6
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Next smaller element between (0 , 5) is 6
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result : [-1, 2, 2, 3, 3, 4, 6]
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1) Create a new empty stack st
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2) Iterate over array "input" , where "i" goes from 0 to input.length -1.
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a) We are looking for value just smaller than `input[i]`. So keep popping from "stack"
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till elements in "stack.peek() >= input[i]" or stack becomes empty.
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b) If the stack is non-empty, then the top element is our previous element. Else the
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previous element does not exist. c) push input[i] in stack. 3) If elements are left then their
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answer is -1
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*/
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public class NextSmallerElement {
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public static int[] findNextSmallerElements(int[] array) {
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// base case
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if (array == null) {
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return array;
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}
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Stack<Integer> stack = new Stack<>();
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int[] result = new int[array.length];
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Arrays.fill(result, -1);
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for (int i = 0; i < array.length; i++) {
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while (!stack.empty() && stack.peek() >= array[i]) stack.pop();
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if (stack.empty()) {
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result[i] = -1;
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} else {
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result[i] = stack.peek();
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}
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stack.push(array[i]);
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}
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return result;
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}
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public static void main(String[] args) {
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int[] input = {2, 7, 3, 5, 4, 6, 8};
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int[] result = findNextSmallerElements(input);
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System.out.println(Arrays.toString(result));
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}
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}
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