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Add optimized version of DijkstraAlgorithm (#6088)
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package com.thealgorithms.datastructures.graphs;
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import java.util.Arrays;
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import java.util.Set;
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import java.util.TreeSet;
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import org.apache.commons.lang3.tuple.Pair;
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/**
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* Dijkstra's algorithm for finding the shortest path from a single source vertex to all other vertices in a graph.
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*/
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public class DijkstraOptimizedAlgorithm {
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private final int vertexCount;
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/**
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* Constructs a Dijkstra object with the given number of vertices.
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*
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* @param vertexCount The number of vertices in the graph.
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*/
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public DijkstraOptimizedAlgorithm(int vertexCount) {
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this.vertexCount = vertexCount;
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}
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/**
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* Executes Dijkstra's algorithm on the provided graph to find the shortest paths from the source vertex to all other vertices.
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*
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* The graph is represented as an adjacency matrix where {@code graph[i][j]} represents the weight of the edge from vertex {@code i}
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* to vertex {@code j}. A value of 0 indicates no edge exists between the vertices.
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*
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* @param graph The graph represented as an adjacency matrix.
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* @param source The source vertex.
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* @return An array where the value at each index {@code i} represents the shortest distance from the source vertex to vertex {@code i}.
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* @throws IllegalArgumentException if the source vertex is out of range.
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*/
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public int[] run(int[][] graph, int source) {
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if (source < 0 || source >= vertexCount) {
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throw new IllegalArgumentException("Incorrect source");
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}
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int[] distances = new int[vertexCount];
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boolean[] processed = new boolean[vertexCount];
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Set<Pair<Integer, Integer>> unprocessed = new TreeSet<>();
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Arrays.fill(distances, Integer.MAX_VALUE);
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Arrays.fill(processed, false);
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distances[source] = 0;
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unprocessed.add(Pair.of(0, source));
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while (!unprocessed.isEmpty()) {
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Pair<Integer, Integer> distanceAndU = unprocessed.iterator().next();
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unprocessed.remove(distanceAndU);
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int u = distanceAndU.getRight();
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processed[u] = true;
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for (int v = 0; v < vertexCount; v++) {
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if (!processed[v] && graph[u][v] != 0 && distances[u] != Integer.MAX_VALUE && distances[u] + graph[u][v] < distances[v]) {
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unprocessed.remove(Pair.of(distances[v], v));
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distances[v] = distances[u] + graph[u][v];
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unprocessed.add(Pair.of(distances[v], v));
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}
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}
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}
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return distances;
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}
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}
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