algorithm/Java
1
0
Fork 0
mirror of https://github.com/TheAlgorithms/Java.git synced 2025-12-19 07:00:35 +08:00
Code Issues Packages Projects Releases Wiki Activity

refactor: unified duplicate Anagram classes into a single implementation (#6290)

Browse Source
This commit is contained in:
Deniz Altunkapan
2025-06-11 19:04:06 +02:00
committed by GitHub
parent 0b21bb0a38
commit 1745d19f09
9 changed files with 38 additions and 212 deletions
Download Patch File Download Diff File Expand all files Collapse all files

35
src/main/java/com/thealgorithms/strings/Anagrams.java
View File

@@ -23,7 +23,9 @@ public final class Anagrams {
* @param t the second string
* @return true if the strings are anagrams, false otherwise
*/
public static boolean approach1(String s, String t) {
public static boolean areAnagramsBySorting(String s, String t) {
s = s.toLowerCase().replaceAll("[^a-z]", "");
t = t.toLowerCase().replaceAll("[^a-z]", "");
if (s.length() != t.length()) {
return false;
}
@@ -43,17 +45,18 @@ public final class Anagrams {
* @param t the second string
* @return true if the strings are anagrams, false otherwise
*/
public static boolean approach2(String s, String t) {
if (s.length() != t.length()) {
return false;
public static boolean areAnagramsByCountingChars(String s, String t) {
s = s.toLowerCase().replaceAll("[^a-z]", "");
t = t.toLowerCase().replaceAll("[^a-z]", "");
int[] dict = new int[128];
for (char ch : s.toCharArray()) {
dict[ch]++;
}
int[] charCount = new int[26];
for (int i = 0; i < s.length(); i++) {
charCount[s.charAt(i) - 'a']++;
charCount[t.charAt(i) - 'a']--;
for (char ch : t.toCharArray()) {
dict[ch]--;
}
for (int count : charCount) {
if (count != 0) {
for (int e : dict) {
if (e != 0) {
return false;
}
}
@@ -70,7 +73,9 @@ public final class Anagrams {
* @param t the second string
* @return true if the strings are anagrams, false otherwise
*/
public static boolean approach3(String s, String t) {
public static boolean areAnagramsByCountingCharsSingleArray(String s, String t) {
s = s.toLowerCase().replaceAll("[^a-z]", "");
t = t.toLowerCase().replaceAll("[^a-z]", "");
if (s.length() != t.length()) {
return false;
}
@@ -96,7 +101,9 @@ public final class Anagrams {
* @param t the second string
* @return true if the strings are anagrams, false otherwise
*/
public static boolean approach4(String s, String t) {
public static boolean areAnagramsUsingHashMap(String s, String t) {
s = s.toLowerCase().replaceAll("[^a-z]", "");
t = t.toLowerCase().replaceAll("[^a-z]", "");
if (s.length() != t.length()) {
return false;
}
@@ -123,7 +130,9 @@ public final class Anagrams {
* @param t the second string
* @return true if the strings are anagrams, false otherwise
*/
public static boolean approach5(String s, String t) {
public static boolean areAnagramsBySingleFreqArray(String s, String t) {
s = s.toLowerCase().replaceAll("[^a-z]", "");
t = t.toLowerCase().replaceAll("[^a-z]", "");
if (s.length() != t.length()) {
return false;
}