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Add the retrieval of minimum and maximum element from stack at O(1) (#5714)
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package com.thealgorithms.stacks;
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import java.util.NoSuchElementException;
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import java.util.Stack;
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/**
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* A class that implements a stack that gives the maximum element in O(1) time.
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* The mainStack is used to store the all the elements of the stack
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* While the maxStack stores the maximum elements
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* When we want to get a maximum element, we call the top of the maximum stack
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*
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* Problem: https://www.baeldung.com/cs/stack-constant-time
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*/
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public class GreatestElementConstantTime {
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private Stack<Integer> mainStack; // initialize a mainStack
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private Stack<Integer> maxStack; // initialize a maxStack
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/**
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* Constructs two empty stacks
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*/
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public GreatestElementConstantTime() {
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mainStack = new Stack<>();
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maxStack = new Stack<>();
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}
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/**
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* Pushes an element onto the top of the stack.
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* Checks if the element is the maximum or not
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* If so, then pushes to the maximum stack
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* @param data The element to be pushed onto the stack.
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*/
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public void push(int data) {
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if (mainStack.isEmpty()) {
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mainStack.push(data);
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maxStack.push(data);
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return;
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}
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mainStack.push(data);
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if (data > maxStack.peek()) {
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maxStack.push(data);
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}
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}
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/**
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* Pops an element from the stack.
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* Checks if the element to be popped is the maximum or not
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* If so, then pop from the minStack
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*
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* @throws NoSuchElementException if the stack is empty.
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*/
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public void pop() {
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if (mainStack.isEmpty()) {
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throw new NoSuchElementException("Stack is empty");
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}
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int ele = mainStack.pop();
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if (ele == maxStack.peek()) {
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maxStack.pop();
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}
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}
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/**
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* Returns the maximum element present in the stack
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*
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* @return The element at the top of the maxStack, or null if the stack is empty.
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*/
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public Integer getMaximumElement() {
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if (maxStack.isEmpty()) {
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return null;
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}
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return maxStack.peek();
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}
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}
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package com.thealgorithms.stacks;
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import java.util.NoSuchElementException;
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import java.util.Stack;
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/**
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* A class that implements a stack that gives the minimum element in O(1) time.
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* The mainStack is used to store the all the elements of the stack
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* While the minStack stores the minimum elements
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* When we want to get a minimum element, we call the top of the minimum stack
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*
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* Problem: https://www.baeldung.com/cs/stack-constant-time
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*/
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public class SmallestElementConstantTime {
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private Stack<Integer> mainStack; // initialize a mainStack
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private Stack<Integer> minStack; // initialize a minStack
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/**
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* Constructs two empty stacks
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*/
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public SmallestElementConstantTime() {
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mainStack = new Stack<>();
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minStack = new Stack<>();
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}
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/**
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* Pushes an element onto the top of the stack.
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* Checks if the element is the minimum or not
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* If so, then pushes to the minimum stack
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* @param data The element to be pushed onto the stack.
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*/
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public void push(int data) {
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if (mainStack.isEmpty()) {
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mainStack.push(data);
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minStack.push(data);
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return;
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}
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mainStack.push(data);
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if (data < minStack.peek()) {
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minStack.push(data);
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}
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}
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/**
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* Pops an element from the stack.
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* Checks if the element to be popped is the minimum or not
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* If so, then pop from the minStack
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*
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* @throws NoSuchElementException if the stack is empty.
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*/
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public void pop() {
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if (mainStack.isEmpty()) {
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throw new NoSuchElementException("Stack is empty");
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}
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int ele = mainStack.pop();
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if (ele == minStack.peek()) {
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minStack.pop();
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}
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}
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/**
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* Returns the minimum element present in the stack
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*
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* @return The element at the top of the minStack, or null if the stack is empty.
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*/
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public Integer getMinimumElement() {
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if (minStack.isEmpty()) {
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return null;
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}
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return minStack.peek();
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}
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}
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