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Add MinSumKSizeSubarray algorithm (#6025)
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package com.thealgorithms.slidingwindow;
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/**
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* The Sliding Window algorithm is used to find the minimum sum of a subarray
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* of a fixed size k within a given array.
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*
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* <p>
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* Worst-case performance O(n)
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* Best-case performance O(n)
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* Average performance O(n)
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* Worst-case space complexity O(1)
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*
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* This class provides a static method to find the minimum sum of a subarray
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* with a specified length k.
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*
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* @author Rashi Dashore (https://github.com/rashi07dashore)
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*/
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public final class MinSumKSizeSubarray {
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// Prevent instantiation
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private MinSumKSizeSubarray() {
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}
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/**
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* This method finds the minimum sum of a subarray of a given size k.
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*
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* @param arr is the input array where the minimum sum needs to be found
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* @param k is the size of the subarray
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* @return the minimum sum of the subarray of size k
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*/
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public static int minSumKSizeSubarray(int[] arr, int k) {
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if (arr.length < k) {
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return -1; // Edge case: not enough elements
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}
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int minSum;
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int windowSum = 0;
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// Calculate the sum of the first window
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for (int i = 0; i < k; i++) {
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windowSum += arr[i];
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}
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minSum = windowSum;
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// Slide the window across the array
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for (int i = k; i < arr.length; i++) {
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windowSum += arr[i] - arr[i - k];
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minSum = Math.min(minSum, windowSum);
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}
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return minSum;
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}
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}
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@ -0,0 +1,79 @@
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package com.thealgorithms.slidingwindow;
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import static org.junit.jupiter.api.Assertions.assertEquals;
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import org.junit.jupiter.api.Test;
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/**
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* Unit tests for the MinSumKSizeSubarray class.
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*
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* @author Rashi Dashore (https://github.com/rashi07dashore)
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*/
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class MinSumKSizeSubarrayTest {
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/**
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* Test for the basic case of finding the minimum sum.
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*/
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@Test
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void testMinSumKSizeSubarray() {
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int[] arr = {2, 1, 5, 1, 3, 2};
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int k = 3;
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int expectedMinSum = 6; // Corrected: Minimum sum of a subarray of size 3
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assertEquals(expectedMinSum, MinSumKSizeSubarray.minSumKSizeSubarray(arr, k));
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}
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/**
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* Test for a different array and subarray size.
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*/
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@Test
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void testMinSumKSizeSubarrayWithDifferentValues() {
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int[] arr = {1, 2, 3, 4, 5};
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int k = 2;
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int expectedMinSum = 3; // 1 + 2
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assertEquals(expectedMinSum, MinSumKSizeSubarray.minSumKSizeSubarray(arr, k));
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}
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/**
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* Test for edge case with insufficient elements.
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*/
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@Test
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void testMinSumKSizeSubarrayWithInsufficientElements() {
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int[] arr = {1, 2};
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int k = 3; // Not enough elements
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int expectedMinSum = -1; // Edge case
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assertEquals(expectedMinSum, MinSumKSizeSubarray.minSumKSizeSubarray(arr, k));
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}
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/**
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* Test for large array.
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*/
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@Test
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void testMinSumKSizeSubarrayWithLargeArray() {
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int[] arr = {5, 4, 3, 2, 1, 0, -1, -2, -3, -4};
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int k = 5;
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int expectedMinSum = -10; // -1 + -2 + -3 + -4 + 0
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assertEquals(expectedMinSum, MinSumKSizeSubarray.minSumKSizeSubarray(arr, k));
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}
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/**
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* Test for array with negative numbers.
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*/
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@Test
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void testMinSumKSizeSubarrayWithNegativeNumbers() {
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int[] arr = {-1, -2, -3, -4, -5};
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int k = 2;
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int expectedMinSum = -9; // -4 + -5
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assertEquals(expectedMinSum, MinSumKSizeSubarray.minSumKSizeSubarray(arr, k));
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}
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/**
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* Test for the case where k equals the array length.
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*/
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@Test
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void testMinSumKSizeSubarrayWithKEqualToArrayLength() {
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int[] arr = {1, 2, 3, 4, 5};
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int k = 5;
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int expectedMinSum = 15; // 1 + 2 + 3 + 4 + 5
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assertEquals(expectedMinSum, MinSumKSizeSubarray.minSumKSizeSubarray(arr, k));
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}
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}
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